Question

In: Physics

baseball pitcher executes a pitch in 0.32 sec. (assume that his motion of the pitching arm...

baseball pitcher executes a pitch in 0.32 sec. (assume that his motion of the pitching arm is a circular, also assume that v1 = 0). If his pitching arm is 90 cm long, what are the magnitudes of the tangential and radial accelerations on the ball just before ball release, when tangential ball speed is 35 m/s (in m/s2)? What is the magnitude of the total acceleration on the ball at this point (in m/s2)?

Solutions

Expert Solution

Initial speed of the ball = V1 = 0 m/s

Final speed of the ball = V2 = 35 m/s

Length of the pitching arm = L = 90 cm = 0.9 m

Initial angular speed of the ball = 1 = V1/L = 0/0.9 = 0 rad/s

Final angular speed of the ball = 2 = V2/L = 35/0.9 = 38.889 rad/s

Time period = T = 0.32 sec

Angular acceleration =

2 = 1 + T

38.889 = 0 + (0.32)

= 121.528 rad/s2

Radial acceleration of the ball just before the release = ar

ar = 22L

ar = (38.889)2(0.9)

ar = 1361.11 m/s2

Tangential acceleration of the ball just before the release = at

at = L

at = (121.528)(0.9)

at = 109.37 m/s2

Total acceleration of the ball = a

a = 1365.5 m/s2

a) Magnitude of tangential acceleration of the ball just before the release = 109.37 m/s2

b) Magnitude of radial acceleration of the ball just before the release = 1361.11 m/s2

c) Total acceleration of the ball just before the release = 1365.5 m/s2


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