In: Statistics and Probability
A lumber company is making boards that are 2709 millimeters tall. If the boards are too long they must be trimmed, and if they are too short they cannot be used. A sample of 38 boards is taken, and it is found that they have a mean of 2711.5 millimeters. Assume a population variance of 196. Is there evidence at the 0.05 level that the boards are too long and need to be trimmed?
Step 1 of 6:
State the null and alternative hypotheses.
Step 2 of 6:
Find the value of the test statistic. Round your answer to two decimal places.
Step 3 of 6:
Specify if the test is one-tailed or two-tailed.
Step 4 of 6:
Find the P-value of the test statistic. Round your answer to four decimal places.
Step 5 of 6:
Identify the level of significance for the hypothesis test.
Step 6 of 6:
Make the decision to reject or fail to reject the null hypothesis
1 Tailed Z test, Single Mean
Given:
= 2709 mm,
= 2711 mm,
= 196,
therefore
= 14, n = 38,
= 0.05
(1) The Hypothesis:
H0:
= 2709: The mean height of the boards is equal to 2709 mm.
Ha:
> 2709: The mean mean height of the boards is greater than 2709
mm.
(2) The Test Statistic: The test statistic is given by the equation:
Z observed = 1.10
(3) Tail of the Test: This is a 1 tailed test (Right tailed)
(4) The p Value: The p value for Z = 1.10, p value = 0.1357
(5) The Level
of significance, = 0.05
(6) The
Decision Rule: If P value is <
, Then Reject H0.
The
Decision: Since P value (0.1357) is >
(0.05) , We Fail
To Reject H0.
__________________________________________________________
The Conclusion: There isn't sufficient evidence at the 0.05 significance level to conclude that the mean height of the boards is greater than 2709 mm.