For the reaction 4HCl(g) + O2(g)2H2O(g) + 2Cl2(g) H° = -114.4 kJ and S° = -128.9...

For the reaction 4HCl(g) + O2(g)2H2O(g) + 2Cl2(g)

H° = -114.4 kJ and S° = -128.9 J/K The maximum amount of work that could be done when 2.05 moles of HCl(g) react at 308 K, 1 atm is kJ.

Assume that H° and S° are independent of temperature.

Expert Solution

-1 0

4HCl(g) + O2(g) -----> 2H2O(g) + 2Cl2(g)

We know that ΔG = ΔH - T ΔS

= (-114.4 kJ) - ( 308K x (-0.1289 kJ/K))

= -74.7 kJ/mol

Also ΔG = -nFEo

n = number of electrons transferred = 0-(4(-1)) = 4

F = Faraday = 96500 Col

So Eo = -ΔG / (nF )

= 0.129 V

We know that maximum amount of work done = nFEo

= +74.7 kJ/mol

queen_honey_blossom answered 2 years ago

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