Question

Problem

General Statement: Read in a letter and a number. The number indicates how big the letter triangle should be. The number indicating the size of the triangle will have a range from 0 to 250. num>=0 and num<=250

Input: The first number indicates the number of data sets to follow. Each data set will contain one letter and one number. All letter input will be uppercase.

Data File : pr36.dat

Output: Output the letter triangle specified.

Helpful Hints / Assumptions: The letters must wrap around from Z to A. If you start with Z and have to print 5 levels, you must wrap around and start with A after the Z level is complete.

Sample Input :

3

5 A

3 Z

4 C

Sample Output :

A

BB

CCC

DDDD

EEEEE

Z

AA

BBB

C

DD

EEE

FFFF

Answer 1

Pattern.java

import java.io.File;
import java.util.Scanner;

public class Pattern {
   static char letters[] = {'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'};
   public static void main(String[] args) {
       try {
           //reading input file
File file = new File("pr36.dat");
Scanner input = new Scanner(file);
int n = Integer.parseInt(input.nextLine());
for(int i=0;i<n;i++){
String data[] = input.nextLine().split(" ");
int num = Integer.parseInt(data[0]);
char letter = data[1].charAt(0);
//reading number and letter to print
printPattern(num,letter);
}
input.close();
} catch (Exception ex) {
ex.printStackTrace();
}
   }

   private static void printPattern(int num, char letter) {
       //getting index from letters array based on characters
       int index = (int)letter-65;
       for(int i=0;i<num;i++){
           for(int j=0;j<i+1;j++){
               //printing character that many times
               System.out.print(letters[index]);
           }
           //this is to iterate if Z came then make it as A
           index++;
           if(index == 26){
               index = 0;
           }
           System.out.println();
       }
   }
}
pr36.dat

3
5 A
3 Z
4 C