Question

In: Physics

An object with mass 0.190 kg is acted on by an elastic restoring force with force...

An object with mass 0.190 kg is acted on by an elastic restoring force with force constant 10.3 N/m. The object is set into oscillation with an initial potential energy of 0.150 J and an initial kinetic energy of 6.90×10−2 J.

A) What is the amplitude of oscillation?

Express your answer with the appropriate units.

A=

B) What is the potential energy when the displacement is one-half the amplitude?

Express your answer with the appropriate units.

U=

C) At what displacement are the kinetic and potential energies equal?

Express your answer with the appropriate units.

x=

D) What is the value of the phase angle ϕ if the initial velocity is positive and the initial displacement is negative?

Express your answer in radians.

phi =

Solutions

Expert Solution

Hi,

Hope you are doing well.


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PART A:

Given that,

Initial kinetic energy,

Initial potential energy,

Therefore, Total energy,

Force constant,

From Law of conservation of energy, we have,

Therefore Amplitude is given by:

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PART B:

Given that, Displacement of the object,

Therefore, Potential energy is given by

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PART C:

Given that, Kinetic energy = potential energy.

Therefore, Potential energy= (1/2) Total energy

__________________________________________________________________________

PART D:

Initially at, t = 0 s

We have, Initial potential energy,

Therefore, Initial displacement is given by:

Given that, Initial displacement is negative,

We have, Displacement of a simple harmonic motion is given by:

If you are facing any kinds of difficulties, Please let me know. I'm here to help you! Thank you.
__________________________________________________________________________

Hope this helped for your studies. Keep learning. Have a good day.

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