Question

In: Statistics and Probability

Dr. Schmidt want to determine the pulse rate of drinkers is higher than the pulse rate...

Dr. Schmidt want to determine the pulse rate of drinkers is higher than the pulse rate of non-drinkers. Dr. Schmidt took 2 independent samples of adult germans. Use the sample statistic below to test the claim that the pule rat of drinkers is higher than the pulse rate of non drinkers.

Drinkers 100, mean of 87, standard deviation of 4.8

Non-drinkers 100, mean of 84, standard deviation of 5.3

A) Claim, null hypo, alternative hypo

B) Test to be used, what is the P-value?

C.)Classical approach test statistic, and the critical value of it?

D). What is the conclusion.

Expert Solution

H0 : mu1 =mu2
Ha: mu1 > mu2

test statistics:

t = (x1 -x2)/sqrt(s1^2/n1+s2^2/n2)
= ( 87 -84)/sqrt(4.8^2/100 + 5.3^2/100)
= 4.195

SE = sqrt[ (s12/n1) + (s22/n2) ]
(s12/n1)   0.2304
(s22/n2)    0.2809
SE   0.7151

DF = (s12/n1 + s22/n2)2 / { [ (s12 / n1)2 / (n1 - 1) ] + [ (s22 / n2)2 / (n2 - 1) ] }
[ (s12 / n1)2 / (n1 - 1) ]            0.001
[ (s22 / n2)2 / (n2 - 1) ]           0.00
(s12/n1 + s22/n2)2           0.26
DF =    196

p value = 0

c)

Critical value = 1.653 at 0.05 significance level

Reject H0 if t > 1.653

d)

Reject H0

There is sufficient eviden ceto support the claim that the pulse rate of drinkers is higher than the pulse rate of non-drinkers.

orchestra answered 2 years ago

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