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With the following data, use the method of initial rates to find the reaction orders with...

With the following data, use the method of initial rates to find the reaction orders with respect to NO and O2.:

Trial [NO]o [O2]o Initial reaction
rate, M/s
1 0.020 0.010 0.028
2 0.020 0.020 0.057
3 0.040 0.020 0.227

Solutions

Expert Solution

Rate = K[NO]^m[O2]^n

0.028   = K(0.02)^m *(0.01)^n ------------------------> 1

0.057   = K(0.02)^m*(0.02)^n -------------------------> 2

0.227    = K(0.04)^m*(0.02)^n -------------------------> 3

eq 1 is divide with eq 2

0.028/0.057 = K(0.02)^m *(0.01)^n/K(0.02)^m*(0.02)^n

0.5                 = (0.01/0.02)^n

(0.5)^1                 = (0.5)^n

   n                  = 1

eq 2 is divide with eq 3

0.057/0.227 = K(0.02)^m*(0.02)^n/K(0.04)^m*(0.02)^n

0.25             = (0.02/0.04)^m

0.25            = (0.5)^m

(0.5)^2     = (0.5)^m

m     = 2

rate law

Rate = K[NO]^2[O2]^1

order with respect NO = 2

order with respect O2 = 1

queen_honey_blossom answered 2 years ago
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