Question

The Fermi energy for copper is EF = 7.00 eV. For copper at T = 1030 K, (a) find the energy of the energy level whose probability of being occupied by an electron is 0.933. For this energy, evaluate (b) the density of states N(E) and (c) the density of occupied states No(E).

Answer 1

(a)Let the  energy of the energy level whose probability of being occupied by an electron is 0.933 is

Given fermi energy for copper is

We know that

gives us the probability of a certain energy level occupied by an electron at temperature T .

k is known as Boltzman constant=

So by the problem statement

Or

Or

Or

Or

Or

b) The density of states at an energy    is given by

Where 'm' is the mass of electron

'h' is the Planck's constant

So

c) The density of occupied states at an energy    is s given by