Question

In: Physics

A projectile is fixed at an upward angle of 38.0 degrees from the top of a...

A projectile is fixed at an upward angle of 38.0 degrees from the top of a 105m high cliff speed of 165m/s. What is it’s speed when it strikes the ground? Please show all work.

Expert Solution

Given launching speed ,u =165 m/s

Angle of projectile launch ,

The launching speed can be split into its components u_x and u_y ,Where

Since there is no acceleration in horizontal direction value of u_x don't change

so

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Consider vertical motion of horizontal

Rising Part

At max height, Velocity in vertical direction becomes zero

Use Formula v² -u² =2as

gravity is acting downwards

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Now Falling Part

Total Distance to cover = s +height of cliff = 525.96 +105 =630.96 m

Initial vertical velocity is Zero

Use Formula v² -u² =2as

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ANSWER:

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genius_generous answered 8 months ago

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