In: Chemistry
You determined the theoretical yield if 0.5 moles of zinc is used to form ZnI2. Determine the percent yield if 515.6 g of product is recovered.
___ Zn + __I2 → ___ZnI2
Zn + I2 ------------> ZnI2
1 moles of Zn react with I2 to gives 1 mole of ZnI2
0.5moles of Zn react with I2 to gives = 1*0.5/1 = 0.5 moles of ZnI2
actual yield yield of ZnI2 = no of moles * molar mass of ZnI2
= 0.5*319.22
= 159.61g
percent yield = actual yield *100/theoretical yield
= 159.61*100/515.6 = 30.96% >>>>>answer