Question

In: Chemistry

Nickel and aluminum react within a voltaic cell. Calculate the voltage of the standard cell. If...

Nickel and aluminum react within a voltaic cell. Calculate the voltage of the standard cell. If the solutions contain 1.5 M Ni2+ and 0.6 M Al3+, what is the initial voltage?

Solutions

Expert Solution

          Al(s)-------------------> Al^3+ (aq) + 3e^-      E0 =1.66v

         Ni^2+ (aq) + 2e^- ----------> Ni(s)               E0 = -0.23v

           2Al(s)-------------------> 2Al^3+ (aq) + 6e^-      E0 =1.66v

         3Ni^2+ (aq) + 6e^- ----------> 3Ni(s)                E0 = -0.23v

-----------------------------------------------------------------------------------------------

    2Al(s) + 3Ni^2+ (aq) ---------------> 2Al^3+(aq) + 3Ni(s)    E0 cell = 1.43v

      n =6

        Ecell   = E0cell - 0.0592/n logQ

                   = 1.43 -0.0592/6 log[Al^3+]^2/[Ni}^3

                   = 1.43 - 0.00986log(0.6)2/(1.5)^3

                   = 1.43 - 0.00986*-0.9719

                     = 1.4395v >>>>answer


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