Nickel and aluminum react within a voltaic cell. Calculate the voltage of the standard cell. If...

Nickel and aluminum react within a voltaic cell. Calculate the voltage of the standard cell. If the solutions contain 1.5 M Ni2+ and 0.6 M Al3+, what is the initial voltage?

Expert Solution

Al(s)-------------------> Al^3+ (aq) + 3e^- E0 =1.66v

Ni^2+ (aq) + 2e^- ----------> Ni(s) E0 = -0.23v

2Al(s)-------------------> 2Al^3+ (aq) + 6e^- E0 =1.66v

3Ni^2+ (aq) + 6e^- ----------> 3Ni(s) E0 = -0.23v

-----------------------------------------------------------------------------------------------

2Al(s) + 3Ni^2+ (aq) ---------------> 2Al^3+(aq) + 3Ni(s) E0 cell = 1.43v

n =6

Ecell = E0cell - 0.0592/n logQ

= 1.43 -0.0592/6 log[Al^3+]^2/[Ni}^3

= 1.43 - 0.00986log(0.6)2/(1.5)^3

= 1.43 - 0.00986*-0.9719

= 1.4395v >>>>answer

queen_honey_blossom answered 2 years ago

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