In: Statistics and Probability
A new soft drink is being market tested. It is estimated that 60% of consumers will like
the new drink. A sample of 96 taste-tested the new drink.
(a) Determine the standard error of the proportion.
(b) What is the probability that more than 70% of consumers will indicate they like the drink?
Solution:
Given that,
n = 96
= 0.60
1 -
= 1 - 0.60 = 0.40
So,
a )
=
= 0.60
Expected value = 0.60
=
( 1 -
) / n
=
0.60 * 0.40 / 96
= 0.05
= 0.05
Standard error = 0.05
b) P (
> 0.70 )
= 1 - P (
< 0.70 )
= 1 - P (
-
/
) < ( 0.70 - 0.60 / 0.05 )
= 1 - P( z < 0.1 / 0.05 )
= 1 - P ( z < 2 )
Using z table
= 1 - 0.9772
= 0.0228
Probability = 0.0228