In: Math
Please show work - trying to understand how to do this so I can apply it to other problems.
Both Professor X and Professor Y agree that students who study for their examinations do better than those who do not. Both professors teach the same class, take a careful four level ranking of how hard their students studied and give a very similar examination.
This year the average score in Professor X’s class and the average score in Professor Y’s class by their level of study effort was virtually THE SAME:
Students who studied seriously scored an average of 100 points
Students who studied moderately earned an average of 80 points
Students who studies briefly earned an average of 60 points
Students who did not study earned an average of 40 points
Professor X Professor Y
Class size 100 class size 100
20% of students Studied Seriously 40% of students studied seriously
40% of students studied moderately 40% of students studied moderately
30% of students studied briefly 10% of students studies briefly
10% of students did not study at all 10% of students did not study at all
What is the average score in Professor X’s class? In Professor Y’s class?
What would be the average scores if both Professors had the SAME composition of students (in relation to the level of effort in studying)
the following table shows the different levels of effort, average scores for each level of effort and the proportion of students in who put in the efforts at each level in 2 classes
Professor X | Professor Y | ||
the level of effort in studying | Average score | Percentage of students | Percentage of students |
Studied Seriously | 100 | 20% | 40% |
studied moderately | 80 | 40% | 40% |
studied briefly | 60 | 30% | 10% |
did not study at all | 40 | 10% | 10% |
The average score of any given class is
the average score in professor X's class is
the average score in professor Y's class is
If the composition of students, in relation to the level of effort in studying, is the same then the proportion of students in each effort level is 25% (There are 4 groups and hence the proportion of students at each level of effort is 1/4*100=25%
the average score if both Professors had the SAME composition of students
which is the average of 100,80,60, and 40 , that is (100+80+60+40)/4