Question

You mix 55 mL of 1.00

M

silver nitrate with 25 mL of 1.17

M

sodium chloride. What mass of

silver chloride should you form?

Answer 1

   AgNo3(aq) + NaCl(aq)---------------> AgCl (s) + NaNO3(aq)

no of moles of AgNo3 = molarity * volume in L

                                     = 1*0.055   = 0.055 moles

no of moles of NaCl     = molarity * volume in L

                                     = 1.17*0.025   = 0.02925 moles

fram balanced equation

1 mole of AgNo3 react with 1 mole of NaCl

0.055 moles of AgNO3 react with 0.055 moles of NaCl

NaCl is limiting reactant

1 mole of NaCl react with AgNo3 to gives 1 mole of AgCl

0.02925 moles of NaCl react with AgNo3 to gives 0.02925 moles of AgCl

mass of AgCl = no of moles * gram molar mass

                       = 0.02925*143.5   = 4.197g of AgCl