For a small scale hydraulic power system, the elevation difference between the reservoir water surface and...

For a small scale hydraulic power system, the elevation difference between the reservoir water surface and the pond water surface downstream of the reservoir is 20.35. The velocity of the water exhausting into the pond is 7 m/s, and the discharge through the system is 4 m³/s. The head loss due to friction in the penstock (inlet pipe to turbine, under very high pressure) is negligible. Find the power produced by the turbine in kilowatts. Assume specific weight of water is 9810 N/m³ and g = 9.81 m/s²

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Solution posted below

As the pipe is in high pressure which implies that the velocity of flow should be low i.e. the flow should be laminar. But i've calculated both the possibilities of flow i.e. laminar or turbulent flow.

Efficiency of system has not given in the question so I've assumed it to be 85%.. If u know the exact efficiency so u can easily replace it by 85%.

Hope it helps.

Ally Wells answered 2 months ago

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