Question

HCS12 Assembly code please.

Translate the following code into assembly. Allocate each variable on the stack. Simulate your

program and screenshot the final value of the variables in memory.

{

char A,B,C;

int F;

A = 2;

B = 6;

C =

-

10;

F = (A + B)*C;

C = F

+10

}

Answer 1

Below is the program converted into assembly language.

main:
        push    rbp
        mov     rbp, rsp
        mov     BYTE PTR [rbp-1], 2
        mov     BYTE PTR [rbp-2], 6
        mov     BYTE PTR [rbp-3], -10
        movsx   edx, BYTE PTR [rbp-1]
        movsx   eax, BYTE PTR [rbp-2]
        add     edx, eax
        movsx   eax, BYTE PTR [rbp-3]
        imul    eax, edx
        mov     DWORD PTR [rbp-8], eax
        mov     eax, DWORD PTR [rbp-8]
        add     eax, 10
        mov     BYTE PTR [rbp-3], al
        mov     eax, 0
        pop     rbp
        ret

This is the output log of the following asm program and the final values of variables.

ASM generation compiler returned: 0

Execution build compiler returned: 0

Program returned: 0

2,6,-70,-80

PS: The statement I added to know the final values of variables(converted into C) :  printf("%d,%d,%d,%d",A,B,C,F);

So, A=2, B=6, C=-70, F=-80