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Question: In the following MIPS assembly code, translate all the instructions to their corresponding machine code...

Question: In the following MIPS assembly code, translate all the instructions to their corresponding machine code in hexadecimal format. This code is stored in the memory from address 0x2fff0004.

Loop: lw $t0, 4($s0)

addi $t1, $t1, -15

sll $t1, $t1, 2

beq $t1, $s1, Exit

addi $s0, $s0, 4

j Loop

Exit: …

Expert Solution

Please find the answer below::

LW $t0 0x0004 $s0

For the instruction, the format is as below

Binary: 10001110000010000000000000000100

Hex: 0x8e080004

2. addi $t1, $t1, -15

Instruction is as below

ADDI $t1 $t1 0xFFF1

Binary: 00100001001010011111111111110001

Hex: 0x2129fff1

3.

sll $t1, $t1, 2

Binary: 00000000000010010100100010000000

Hex: 0x00094880

4.

BEQ $t1 $s1 0x0002

Binary: 00010001001100010000000000000010

Hex: 0x11310002

5.

ADDI $s0 $s0 0x0004

Binary: 00100010000100000000000000000100

Hex: 0x22100004

6.

j Loop

Address of loop is : 0x2fff0004

IN binary it is:

101111111111110000000000000100

Converting to 26 bit it will be :

11111111111100000000000001

Adding 000010 as MSD for jump

SO complete instruction will be : 00001011111111111100000000000001

In hexa decimal it will be : 0xbffc001

venereology answered 3 months ago

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