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Consider the titration of a 19.5 mL sample of 0.903 M HC2H3O2 with 0.18 M NaOH....

Consider the titration of a 19.5 mL sample of 0.903 M HC2H3O2 with 0.18 M NaOH. Ka(HC2H3O2) = 1.8x10-5 Determine the pH at the equivalence point. Enter to 4 decimal places.

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Expert Solution

pH = 8.9605

queen_honey_blossom answered 9 months ago
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