In: Statistics and Probability
A noted psychic was tested for ESP. The psychic was presented with 400 cards face down and asked to determine if each of the cards was one of four symbols: a star, cross, circle, or square. The psychic was correct in 120 cases. Based on chance alone, the expected probability that a card will be chosen correctly is ¼. Fill out the table below of observed and expected counts. Psychic’s Outcome Observed Expected Correct 120 Incorrect Total 400 400 Calculate χ² components. Psychic’s Outcome χ² components Correct Incorrect Total Is she really psychic? Check for evidence that the proportion of cards correctly identified by the psychic is significantly different than expected based on chance alone. Complete the table below.
Test type: |
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Null hypothesis: |
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Alt hypothesis: |
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Test-statistic: |
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p-value: |
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Conclusion: |
Psychic’s Outcome χ² components
Correct
Incorrect
Total
Test type: Chi-Square Test for Homogeneity
Null hypothesis H0: Proportion of cards correctly identified by the psychic is same as expected based on chance alone (1/4) |
Alternative hypothesis H1: Proportion of cards correctly identified by the psychic is different than expected based on chance alone (1/4)
Expected count for correct cases = 400 * 1/4 = 100
Expected count for incorrect cases = 400 * 3/4 = 300
Observed count for correct cases = 120
Observed count for incorrect cases = 400 - 120 = 280
Psychic’s Outcome χ² components
Correct (120 - 100)2 / 100 = 4
Incorrect (280 - 300)2 / 300 = 1.33
Total 4 + 1.33 = 5.33
Test-statistic: 5.33
Degree of freedom = Number of cases - 1 = 2 - 1 = 1
p-value = P(χ² > 5.33, df = 1) = 0.021
Since p-value is less than 0.05 significance level, we reject null hypothesis H0 and conclude that there is significant evidence that proportion of cards correctly identified by the psychic is significantly different than expected based on chance alone (1/4)