Question
In: Civil Engineering
The laboratory analysis of 25 mL sample after filtration gave the following data: Weight of the...
- The laboratory analysis of 25 mL sample after filtration gave the following data:
- Weight of the filter disk after drying at 103 oC and 550 oC = 5.31g
- Weight of the filter disk and sample after drying at 103 oC = 5.374g
- Weight of the filter disk and sample after igniting at 550 oC = 5.339g
Determine the concentrations (in mg/L) of: a) Total suspended solids (TSS), b) Volatile suspended solids (VSS), and c) Fixed suspended solids (FSS) of the water sample.
Solutions
Ally Wells answered 3 months agoRelated Solutions
A random sample of communities in western Kansas gave the following information for people under 25...
A random sample of communities in western Kansas gave the
following information for people under 25 years of age. Rate of hay
fever per 1000 population for people under 25 124 96 98 107 120 122
142 136 112 124 81 124 108 120 144 115 A random sample of regions
in western Kansas gave the following information for people over 50
years old. : Rate of hay fever per 1000 population for people over
50 87 103 100 98...
A sample of biological culture was submitted to a chemical laboratory for analysis of the percentage...
A sample of biological culture was submitted to a chemical
laboratory for analysis of the percentage by weight of each major
element. The composition of the cells by weight was found to be
48.9% C, 5.2% H, 24.8% O, 9.46% N, and 9.2% ash.
Prepare an empirical formula for the cells
Determine the COD/organic weight ratio for the cell
Determine the theoretical oxygen demand including both COD and
NOD
(nitrification oxygen demand)
If the organics are 80% biodegradable, what is...
2. Following is the weight data (in grams) of 25 tea bags samples produced by a...
2. Following is the weight data (in grams) of 25 tea bags
samples produced by a machine in 1 hour: 5.65 5.44 5.42 5.40 5.53 |
5.34 5.54 5.45 5.52 5.41 | 5.57 5.40 5.53 5.54 5.55 | 5.62 5.56
5.46 5.44 5.51 | 5.47 5.40 5.47 5.61 5.53 |
a. Calculate the average, median, quartile 1 and quartile 3
b. Calculate range, interquartile range, variance, standard
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c.Draw the boxplot, give a conclusion
A random sample of 5 states gave the following areas (in 1000 square miles; same data...
A random sample of 5 states gave the following areas (in 1000
square miles; same data as Problem 2-38, incidentally): 147, 84,
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for all 50 states in the United States. 13. A real estate agent
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A Sample of coarse grained soil tested in the laboratory. The gradation analysis results are as...
A Sample of coarse grained soil tested in the
laboratory. The gradation analysis results are as shown
in the table below.
Sieve Size
(mm)
Mass retained on
each sieve (g)
4.75 0
2.00 40
0.850 60
0.425 89
0.250 140
0.180 122
0.150 210
0.075 56
Pan 12
Classify the soil according to Unified Soil Classification System
(USCS)
QUESTION 2 [25] After submitting your analysis, Chihiro noticed that the data she collected can be...
QUESTION 2
[25] After submitting your analysis, Chihiro noticed that the
data she collected can be organized by the day of the week as can
be seen in the following table.
Vancouver
Saskatoon
Montreal
Halifax
Sums
Means
Monday
72
75
78
76
301
75.25
Tuesday
74
77
77
73
301
75.25
Wednesday
73
75
79
70
297
74.25
Thursday
75
73
76
75
299
74.75
Friday
68
67
72
65
272
68
Sums
362
367
382
359
1470
Means
72.4...
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A 15.6g sample of C6H6 reacts with an excess of HNO3. After the laboratory process, 18.0g...
A
15.6g sample of C6H6 reacts with an excess of HNO3. After the
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C6H6 + HNO3 → C6H5NO2 + H2O
The following data represent the weight (in grams) of a random sample of 13 medicine tablets....
The following data represent the weight (in grams) of a random
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0.600 0.598 0.598 0.600 0.600 0.599 0.604 0.611 0.606 0.599
0.601 0.602 0.604
find the five number summary
The data for a sample of 100 gave the regression line equation for age and blood...
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Select one:
A. 155.08
B. 159.08
C. 149.09
D. 151.08
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