Consider the following reaction at 388 K 2SO2 (g) + O2 (g) <==> 2SO3 (g) At...

Consider the following reaction at 388 K
2SO2 (g) + O2 (g) <==> 2SO3 (g)
At equilibrium the reaction mixture contains 1.28 atm of O2 and 6.78 atm of SO3. The
equilibrium constant, KP, at this temperature is 46.7. Calculate the equilibrium partial
pressure of SO2.

Expert Solution

2SO₂ (g) + O₂ (g) 2SO₃ (g)

Equb pressure(atm) a 1.28 6.78

Given Equilibrium constant , K_p = 46.7

Equilibrium constant , K_p = p²_SO3 / ( p²_SO2 x p _O2 )

46.7 = 6.78² / (a² x 1.28)

a² = 0.769

a = 0.88 atm

Therefore the equilibrium partial pressure of SO₂ is = a = 0.88 atm

queen_honey_blossom answered 2 years ago

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