The real ammeter (with 0 resistance) and voltmeter (with infinity resistance) do not achieve ideal values...

The real ammeter (with 0 resistance) and voltmeter (with infinity resistance) do not achieve ideal values (When using in a lab), but can behave as "effectively ideal" under some conditions. what are those conditions? and what are the approximate value of resistances of the meters that normally use in labs?

Expert Solution

Manojponduru answered 8 months ago

Using a voltmeter and Ammeter, Draw two optimal circuits to measure both low resistance and high...

Using a voltmeter and Ammeter, Draw two optimal circuits to measure both low resistance and high resistance. Describe the source of error ( in readings) in both circuits

electrical resistance 1. The high-resistance paper has a resistivity of 1:25 Ωm. How do your values...

electrical resistance 1. The high-resistance paper has a resistivity of 1:25 Ωm. How do your values compare? What are possible causes for discrepancies between the known value and your calculated values? Resistivity measurements Measured resistance Length Width Cross-sectional area Resistivity (Ω) (m) (m) (m2) (Ω·m) 1 18.6 .052 .015 .00078 .000134 2 17.5 .076 .02 .00152 .001151 3 52. .10 .01 .001 .001300 4 5 6 ** thickness = .25 mm 2. What are possible causes for discrepancies between theoretical...

For which real values of a do there exist solutions of the differential equation y'' +...

For which real values of a do there exist solutions of the differential equation y'' + 2y' + ay = 0 which satisfy the conditions y(0) = y(π) = 0 but which are not identically zero? For each such a give an appropriate non-zero solution

How do major real estate companies impact market conditions and values?

We will now simulate numpy.random(), which produces floating-point values in the range [0..1). To do this,...

We will now simulate numpy.random(), which produces floating-point values in the range [0..1). To do this, it is simply necessary to convert integers in the range [0..?)[0..m) returned by my_random_int() to floating point numbers in the range [0..1).[0..1). Hint: Easily done by division! # my_random returns a random floating-point number within [0, 1) def my_random(): # your code here return 0 # just to get it to compile # Test it! my_seed(0) for x in range(0,10): print(my_random()) CODE GIVEN: a...

Question