Calculate the equilibrium constant for each of the reactions at 25 ∘C. Part B O2(g)+2H2O(l)+2Cu(s)→4OH−(aq)+2Cu2+(aq) Express...

Calculate the equilibrium constant for each of the reactions at 25 ∘C.

Part B

O2(g)+2H2O(l)+2Cu(s)→4OH−(aq)+2Cu2+(aq)

Express your answer using two significant figures.

Solutions

Expert Solution

2Cu(s) ------------------------------> 2Cu^2+ (aq) + 4e^- E0 = -0.34v

O2(g) + 2H2O(l) + 4e^- ----------------> 4OH^- (aq) E0 = 0.4v

--------------------------------------------------------------------------------------------------------

O2(g) + 2H2O(l) + 2Cu(s) --------------------> 2Cu^2+ (aq) + 4OH^- (aq) E0cell = 0.06v

n = 4

G⁰ = -nE0cell *F

= -4*0.06*96500 = -23160J

G⁰ = -RTlnK

-23160 = -8.314*298*2.303logK

-23160 = -5705.8483logk

logK = -23160/-5705.8483

logK = 4.06

K = 10^4.06 = 1.15*10^4 >>>>>answer

queen_honey_blossom answered 1 year ago

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