y''+5y'+6y=sint–cos2t

Expert Solution

Colby Messinger answered 2 years ago

Consider the equation y′′ − 5y′ + 6y =e3tcos(2t) + e2t(3t+4)sint (a) Determine a suitable form...

Consider the equation y′′ − 5y′ + 6y =e3tcos(2t) + e2t(3t+4)sint (a) Determine a suitable form for yp if the method of undetermined coefficients is used - Show steps for getting A, B, etc. - if possible, split up the right hand side and handle each value seperately, aka y′′ − 5y′ + 6y =e3tcos(2t), then y′′ − 5y′ + 6y =e2t(3t+4)sint, then adding together for final solution. (b) Find the general solution of the equation.

find a particular solution to y'' + 5y' + 6y = 18te3t Yp=?

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Use variation of parameters to solve the following differential equations y''-5y'-6y=tln(t)

Given the differential equation y’’ +5y’+6y=te^t with start value y(0) = 0 and y’(0). Let Y(s)...

Given the differential equation y’’ +5y’+6y=te^t with start value y(0) = 0 and y’(0). Let Y(s) be the Laplace transformed of y(t). a) Find an expression for Y(s) b) Find the solution to the equation by using inverse Laplace transform.

1) . Solve the IVP: y^''+6y^'+5y=0, y(0)=1, y^' (0)=3 2. Find the general solution to each...

1) . Solve the IVP: y^''+6y^'+5y=0, y(0)=1, y^' (0)=3 2. Find the general solution to each of the following: a) y^''+2y^'+5y=e^2x b) y^''+2x/(x^2+1) y'=x c) y^''+4y=1/(sin⁡(2x)) (use variation of parameters)

ﬁnd the general solution of the given differential equation. 1. y''+2y'−3y=0 2. 6y''−y'−y=0 3. y''+5y' =0 4. y''−9y'+9y=0

Find the solution to the following initial value problem y' -y = t - sint +...

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Let Q1=y(1.1), Q2=y(1.2), Q3=y(1.3), where y=y(x) solves... 1) y'''+2y''-5y'- 6y=4x^2 where y(0)=1, y'(0)=2, y''(0)=3 2) y'''-...

Let Q1=y(1.1), Q2=y(1.2), Q3=y(1.3), where y=y(x) solves... 1) y'''+2y''-5y'- 6y=4x^2 where y(0)=1, y'(0)=2, y''(0)=3 2) y'''- 6y''+11y'- 6y=6e^(4x) where y(0)=4, y'(0)=10, y''(0)=30 3) y''- 6y'+9y=4e^(3x) ln(x) where y(1)=, y'(1)=2 Please show all steps and thank you!!!

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