In: Statistics and Probability
Chapin Manufacturing Company operates 24 hours a day, five days a week. The workers rotate shifts each week. Management is interested in whether there is a difference in the number of units produced when the employees work on various shifts. A sample of five workers is selected and their output recorded on each shift.
At the 0.05 significance level, can we conclude there is a difference in the mean production rate by shift or by employee?
Units Produced Employee Day Afternoon Night
Skaff 31 21 34
Lum 33 25 37
Clark 27 28 38
Treece 33 22 28
Morgan 25 24 36
What is your decision regarding H0? (Round your answers to 2 decimal places.) What is your conclusion?
Here, N = 15 ( NO. OF EMPLOYEES * TIMES = 5 * 3)
k = 3 ( Timings)
The null hypothesis is :
H0: There is no significant difference in the mean production rate by shift or by employee i.e.
The alternative hypothesis is:
H1: There is a significant difference in the mean production rate by shift or by employee i.e.
31 | 33 | 27 | 33 | 25 | 961 | 1089 | 729 | 1089 | 625 |
21 | 25 | 28 | 22 | 24 | 441 | 625 | 784 | 484 | 576 |
34 | 37 | 38 | 28 | 36 | 1156 | 1369 | 1444 | 784 | 1296 |
Grand Total =
Total Sum Of Squares (TSS) =
=
= 2558 + 3083 + 2957 + 2357 + 2497 - [4422/15]
= 427.73
Sum of squares between classes (SST) =
=
=
= 37.07
Sum of Squares within classes (SSE) = TSS - SST = 427.73 - 37.07 = 390.66
The ANOVA table:
Sources of Variation | Sum Of Squares | Degree of Freedom | Mean Sum Of Squares | F-Statistic |
Between Classes | SST | k -1 | SST/ (k-1) = MST | MST/MSE |
Within Classes | SSE | N - k | SSE / (N - k) = MSE | |
Total | TSS | N - 1 |
Putting the values in ANOVA Table:
Sources of Variation | Sum Of Squares | Degree of Freedom | Mean Sum Of Squares | F-Statistic |
Between Classes | 37.07 | 2 | 18.535 | 0.57 |
Within Classes | 390.66 | 12 | 32.55 | |
Total | 427.73 | 14 |
Now, The Tabulated value of F-statistic (see the image below) at (2,12) degrees of freedom at 5% level of significance is 3.88. Since calculated value of F is less than tabulated value of F, therefore H0 is accepted at 5% level of significance.
Hence , there is no significant difference in the mean production rate by shift or by employee.