Question

In: Physics

A) During a lab, a meter stick was used at static equilibrium (the net torque was...

A) During a lab, a meter stick was used at static equilibrium (the net torque was stationary and non-rotating objects are zero) to determine the masses or unknown distances for objects suspended from the meter stick. The total forces exerted at each location along the meter stick were factored in to find the total mass of the slotted masses, the mass hanger, and the clip that was attached to the meter stick. The one mass that did not have to be accounted for in the calculations was the mass of the clip that allowed the meter stick to sit on the pivot point. Why did the mass of the clip not included in the calculations? If the clip was made heavier would the system change at all?

B) If the meter stick was bowed, how would the bowedness effect the ability to calculate the torque accurately due to the force at a given position? What type of error would the bent meter stick produce in the experiment?

Solutions

Expert Solution

(A) In a meter stick experiment the net torque about the fulcrum is is equated to zero for considering the rotational equilibrium of the system (the stick ,the slotted masses, the mass hanger and the clip attached).

All the masses are placed at a certain distance from the fulcrum and they all contribute their part in rotating the system. Since the clip allowes the meter stick to sit on the pivot or the fulcrum. It's always placed where the pivot is. So it's perpendicular distance from the point or the axis of rotation (the pivot) is always considered to be zero. Hence Even if it has certain mass it does not provide any torque. That is the reason why the mass of the clip or precisely the torque due to its weight is not accounted for in the calculations.

Also there would not be any effect of the mass of the clip on the sytem even if it is increased or decreased provided the clip still remains a point object other wise if it would have certain dimensions then even a slight misplacement of the clip might produce error in the calculation of the net torque.

(B) If the meter stick is bowed then yes, it would definitely affect the calculations for torque. We know that torque produced due to any force depends on the perpendicular distance of any force from the point or axis of rotation. The bowedness of the meter stick would definitely decrease the perpendicular distance of the force due to gravity of different masses.

As a result of which the torque calculated for different forces due to the various masses will change which will result in errors.

This type of error would fall under the category of INSTRUMENTAL ERRORS under SYSTEMATIC MEASURMENT ERRORS. Since our instrument is defective due to which we are getting this error. As we would be taking the reading on the meter scale , but the actual perpendicular distance won't be as measured on the meter scale it would be somewhat less than the observed reading as the magnitude of cosine of the angle with which it bowed will be less than 1. Hence l' < l.

Where l' is the actual perpendicular distance. And

l is the measured distance on the meter stick.


Related Solutions

Torque and equilibrium – Lab 07 You have already learned that an unbalanced or net force...
Torque and equilibrium – Lab 07 You have already learned that an unbalanced or net force F accelerate an object, but it is also possible for a balanced set of forces to cause motion. To understand this condition it is necessary to realize that when we deal with real objects they have size and the location of where the force is applied matters. To analyze this motion you must not deal only with the size and direction of F but...
what can you conclude about the relationship of net torque to static equilibrium? explain fully please
what can you conclude about the relationship of net torque to static equilibrium? explain fully please
The center of gravity of the meter stick is 49 cm. mass of meter stick 50...
The center of gravity of the meter stick is 49 cm. mass of meter stick 50 g . mass of hanger #1 =5 g. mass of hanger #2 = 5 g. 1.Place the fulcrum at 51 cm. Attach a 200 g mass, plus hanger #1, at 17 cm on the meter stick and calculate where to attach a 200 g mass, plus hanger #2, to balance it. 2.Balance the stick with the fulcrum at its center of gravity. Attach a...
You attach a meter stick to an oak tree, such that the top of the meter...
You attach a meter stick to an oak tree, such that the top of the meter stick is 2.47 meters above the ground. Later, an acorn falls from somewhere higher up in the tree. If the acorn takes 0.271 seconds to pass the length of the meter stick, how high above the ground was the acorn before it fell, assuming that the acorn did not run into any branches or leaves on the way down? acorn's height: _______m
Lab: Torque and Rotational Equilibrium Data Two Masses in Equilibrium Location of Support (cm) = 50.0...
Lab: Torque and Rotational Equilibrium Data Two Masses in Equilibrium Location of Support (cm) = 50.0 Location of 100 g mass (cm) = 20.0 Location of 200 g mass (cm) = 64.8 Table 1. Calculate: Force (N), Moment Arm (m) = distance, Torque (Nm) Determining an Unknown Mass 2. Determine the mass of the unknown with the beam balance for comparative purposes. Location of Support (cm) = 50.0 Location of 200 g mass (cm) = 23.0 Location of unknown mass...
write about a topics taught in static course(force system resultant, moments, torque, equilibrium of rigid body,...
write about a topics taught in static course(force system resultant, moments, torque, equilibrium of rigid body, frames and machine, structural analysis, internal forces or dry friction) and how it would apply to a field of engineering you are interested in especially civil engineering(or a particular topic of engineering you are not interested in). The statics doesn't have to be the main purpose of the system or topic, but I do want you to discuss how statics fits in. Please write...
•• A meter stick is moving with speed relative to a frame S. (a) What is...
•• A meter stick is moving with speed relative to a frame S. (a) What is the stick’s length, as measured by observers in S, if the stick is parallel to its velocity v? (b) What if the stick is perpendicular to v? (c)What if the stick is at to v, as seen in the stick’s rest frame? [HINT: You can imagine that the meterstick is the hypotenuse of a 30–60–90 triangle of plywood.] (d) What if the stick is...
A meter stick (?= 1.00 m, ?= 100 g) is made into a physical pendulum by...
A meter stick (?= 1.00 m, ?= 100 g) is made into a physical pendulum by drilling a small hole at a distance ?from the center of mass to become the pivot point. Find the distance ?, if the pendulum is to have a period of ?= 3.00 s. A.3.79 cm B.14.6 cm C.20.4 cm D.40.9 cm E.It cannot be done.
(a) Suppose a meter stick made of steel and one made of invar are the same...
(a) Suppose a meter stick made of steel and one made of invar are the same length at 0°C. What is their difference in length at 45.0°C? The coefficient of thermal expansion is 12 ✕ 10−6/°C for steel and 0.9 ✕ 10−6/°C for invar. (b) Repeat the calculation for two 38.5-m-long surveyor's tapes.
(a) Suppose a meter stick made of steel and one made of invar are the same...
(a) Suppose a meter stick made of steel and one made of invar are the same length at 0°C. What is their difference in length at 21.5°C? The coefficient of thermal expansion is 12 ✕ 10−6/°C for steel and 0.9 ✕ 10−6/°C for invar. (b) Repeat the calculation for two 20.5-m-long surveyor's tapes.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT