Question

In: Statistics and Probability

In a poll to estimate presidential popularity, each person in a random sample of 1,190 voters...

In a poll to estimate presidential popularity, each person in a random sample of 1,190 voters was asked to agree with one of the following statements: 1. The president is doing a good job. 2. The president is doing a poor job. 3. I have no opinion. A total of 650 respondents selected the first statement, indicating they thought the president was doing a good job. a. Construct a 95% confidence interval for the proportion of respondents who feel the president is doing a good job. (Use z Distribution Table.) (Round your answers to 3 decimal places.) Confidence interval for the proportion is up to . b. Based on your interval in part (a), is it reasonable to conclude that a majority of the population believes the president is doing a good job?

Solutions

Expert Solution

(a)

n = 1190    

p = 0.546218487    

% = 95    

Standard Error, SE = √{p(1 - p)/n} =    √(0.546218487394958(1 - 0.546218487394958))/1190 = 0.014432219

z- score = 1.959963985    

Width of the confidence interval = z * SE =     1.95996398454005 * 0.0144322191909479 = 0.02828663

Lower Limit of the confidence interval = P - width =     0.546218487394958 - 0.0282866298312457 = 0.51793186

Upper Limit of the confidence interval = P + width =     0.546218487394958 + 0.0282866298312457 = 0.57450512

The confidence interval is [0.518, 0.575]

(b)

The entire interval above is above 50%, so it is reasonable to conclude that a majority of the population believes the president is doing a good job.

[Please give me a Thumbs Up if you are satisfied with my answer. If you are not, please comment on it, so I can edit the answer. Thanks.]


Related Solutions

In a poll to estimate presidential popularity, each person in a random sample of 1,230 voters...
In a poll to estimate presidential popularity, each person in a random sample of 1,230 voters was asked to agree with one of the following statements: The president is doing a good job. The president is doing a poor job. I have no opinion. A total of 675 respondents selected the first statement, indicating they thought the president was doing a good job. Construct a 99% confidence interval for the proportion of respondents who feel the president is doing a...
A sample poll of 100 voters chosen at random from all voters in a given school...
A sample poll of 100 voters chosen at random from all voters in a given school district indicated that 53% of them were in favor of a 1% increase in property taxes in order to provide funds to hire more teachers.           a.       Find the 95% confidence interval for the population proportion of voters supporting the property tax                     hike?           b.       Can we be confident that the tax hike will pass given your results in part (a)? Explain....
12. A recent Gallop poll shows that Trump’s popularity as the presidential candidate is 41% based...
12. A recent Gallop poll shows that Trump’s popularity as the presidential candidate is 41% based on 1,080 people. Find a 90% confidence interval estimate for the true proportion.
A public opinion poll surveyed a simple random sample of 550 voters in Oregon. The respondents...
A public opinion poll surveyed a simple random sample of 550 voters in Oregon. The respondents were asked which political party they identified with most and were categorized by residence. Results are shown below. Decide if voting preference is independent from location of residence. Let α=0.05. Republican Democrat Independent NW Oregon 85 103 22 SW Oregon 45 66 10 Central Oregon 46 53 9 Eastern Oregon 67 33 11 Enter the test statistic - round to 4 decimal places.
A public opinion poll surveyed a simple random sample of 1000 voters. Respondents were classified by...
A public opinion poll surveyed a simple random sample of 1000 voters. Respondents were classified by gender (male or female) and by voting preference (Republican, Democrat, or Independent). Results are shown in the contingency table below.                                                 VOTING PREFERENCES                                                 Rep        Dem      Ind         Row Total Male                                      350         075         25           450 Female                                 275         240         35           550 Column Total                     625         315         60           1000 Is there a gender gap? D3 the men's voting preferences differ significantly from the women's preferences? Use...
Each person in a random sample of 228 male teenagers and a random sample of 305...
Each person in a random sample of 228 male teenagers and a random sample of 305 female teenagers was asked how many hours he or she spent online in a typical week. The sample mean and standard deviation were 15.2 hours and 11.3 hours for males and 14.2 and 11.7 for females. (Use a statistical computer package to calculate the P-value. Use μmales − μfemales. Round your test statistic to two decimal places, your df down to the nearest whole...
In a random sample of 50 voters, intended to show that more voters are in favor...
In a random sample of 50 voters, intended to show that more voters are in favor of candidate A, 34 said they favor candidate A. (a) What is the probability that this many or more voters would favor A is the true proportion of all eligible voters favoring A is 0.54? (b) Is the result significant at the 0.05 level? What about the 0.01 level? Explain your answers.
Suppose a candidate running for Senate in a two-person race commissions a poll of 500 voters...
Suppose a candidate running for Senate in a two-person race commissions a poll of 500 voters and finds that 48 percent are planning on voting for her. The remaining voters in the sample say they are voting for her opponent. a. What is p-hat? b. What is the standard error of p-hat? c. With this estimate of p-hat, the researcher can be sure with 68% confidence that the candidate's true level of support in the population is within what range?...
In a poll, 191 out of a sample of 357 likely Connecticut voters indicate they intend...
In a poll, 191 out of a sample of 357 likely Connecticut voters indicate they intend to vote to legalize marijuana. Find A conservative 99% confidence interval for the proportion of all likely Connecticut voters who are in favor of this initiative. An approximate 95% confidence interval for the same proportion. An improved 90% confidence interval for the same proportion.
A random sample of voters is surveyed to find out if they feel that votes in...
A random sample of voters is surveyed to find out if they feel that votes in Florida should be recounted. The contingency table below shows their opinions and their party affiliation. Can you conclude (using alpha=.1) that party affiliation is independent of a voter’s opinion? Party Affiliation Opinion Republican Democrat Independent Should recount 120 200 22 Should not recount 200 110 30 No opinion 10 50 118
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT