To treat a burn on your hand, you decide to place an ice cube on the...

To treat a burn on your hand, you decide to place an ice cube on the burned skin. The mass of the ice cube is 12.2 g, and its initial temperature is -14.7 °C. The water resulting from the melted ice reaches the temperature of your skin, 29.3 °C. How much heat is absorbed by the ice cube and resulting water? Assume that all the water remains in your hand. Constants may be found here.

Expert Solution

ice converted to water at 0⁰C

q1 = mcT

= 12.2*2.087*(0-(-14.7)

= 12.2*2.087*14.7 = 374.28J

heat of fustion of ice q2 = m*Hvap

= 12.2*333.6 = 4069.92J

ice metl at body temperature q3 = mcT

= 12.2*4.184*(29.3-0)

= 1495.6J

total heat absorbed q = q1+q2+q3

= 374.28 +4069.92+1495.6 = 5939.8J = 5.94KJ

queen_honey_blossom answered 2 years ago

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