Question

In: Statistics and Probability

The prices of Rawlston, Inc. stock (y) over a period of 12 days, the number of...

The prices of Rawlston, Inc. stock (y) over a period of 12 days, the number of shares (in 100s) of company's stocks sold (x1), the volume of exchange (in millions) on the New York Stock Exchange (x2), and the daily profit of the company (in thousands) (x3) are shown below.

day y x1 x2 x3
1 87.50 950 11.00 40
2 86.00 945 11.25 45
3 84.00 940 11.75 27
4 78.00 930 11.75 22
5 84.50 935 12.00 34
6 84.00 935 13.00 51
7 82.00 932 13.25 43
8 80.00 938 14.50 41
9 78.50 925 15.00 45
10 79.00 900 16.50 42
11 77.00 875 17.00 35
12 76.50 870 17.50 34

f.) At a 0.05 significance level, determine which variables are significantly adding to the model from part c and which are not.

g.) Compare the p-values from the simple regression in part a and p-value for the x1 variable in the multiple regression in part f and explain what their difference means.

h.) Were there any variables shown in part f that were not significant? If so remove them and give a new regression model. Is it better than in parts a and/or c? Worse? Why? If it is better use this new one for the remaining problems.

i.) If in a given day, the number of shares of the company that were sold was 91,500, the volume of exchange on the New York Stock Exchange was 19 million, and the company had a profit of $47,000 what would you expect the price of the stock to be? Use whichever model you decided was the best in part h. Also give a 95% prediction interval for your prediction for Stock Price from the Excel output of whichever model you chose.

Solutions

Expert Solution

Using R

> data=read.excel() # Read data

> View(data)

#model

> Model=lm(y~.,data=data)

> summary(Model)

Call:

lm(formula = y ~ ., data = data)

Residuals:

Min 1Q Median 3Q Max

-3.3397 -0.8509 0.2164 1.0543 2.1222

Coefficients:

Estimate Std. Error t value Pr(>|t|)  

(Intercept) 149.42046 62.60706 2.387 0.0441 *

x1 -0.05378 0.06033 -0.891 0.3988  

x2 -1.94061 0.68283 -2.842 0.0217 *

x3 0.21516 0.08547 2.517 0.0360 *

---

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 1.842 on 8 degrees of freedom

Multiple R-squared: 0.8225, Adjusted R-squared: 0.756

F-statistic: 12.36 on 3 and 8 DF, p-value: 0.00226

f.) At a 0.05 significance level, determine which variables are significantly adding to the model from part c and which are not.

---> X2 and X3 and Significant beacuase P-value of both variable is less than 0.05.

g.) Compare the p-values from the simple regression in part a and p-value for the x1 variable in the multiple regression in part f and explain what their difference means.

---->

> SimpleModel=lm(y~x1,data=data)

> summary(SimpleModel)

Call:

lm(formula = y ~ x1, data = data)

Residuals:

Min 1Q Median 3Q Max

-4.1980 -1.0841 0.7839 1.3754 3.0958

Coefficients:

Estimate Std. Error t value Pr(>|t|)

(Intercept) -20.39035 25.21595 -0.809 0.43754

x1 0.11031 0.02731 4.039 0.00237 **

---

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 2.411 on 10 degrees of freedom

Multiple R-squared: 0.62, Adjusted R-squared: 0.582

F-statistic: 16.31 on 1 and 10 DF, p-value: 0.002365

Conclusion- Here difference because when we put x2 and x3 in model then x1 is not significant because x2 and x3 is more important than x1 or more correlated than x1.

h.) Were there any variables shown in part f that were not significant? If so remove them and give a new regression model. Is it better than in parts a and/or c? Worse? Why? If it is better use this new one for the remaining problems.

----> After removing not significant variable x1 new regression model is

> model3=lm(y~x2+x3,data=data)

> summary(model3)

Call:

lm(formula = y ~ x2 + x3, data = data)

Residuals:

Min 1Q Median 3Q Max

-3.3505 -0.8100 0.3582 1.1148 2.0752

Coefficients:

Estimate Std. Error t value Pr(>|t|)   

(Intercept) 93.73127 3.94960 23.732 2e-09 ***

x2 -1.37057 0.23651 -5.795 0.000261 ***

x3 0.16924 0.06741 2.511 0.033282 *  

---

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 1.821 on 9 degrees of freedom

Multiple R-squared: 0.8049, Adjusted R-squared: 0.7616

F-statistic: 18.57 on 2 and 9 DF, p-value: 0.0006396

Conclusion : Yes it is better than part a model because Adjusted R-squared:  0.7616 is increases that's why this one is better model than previous .


Related Solutions

The daily returns for a stock over a period of 110 days are recorded, and the...
The daily returns for a stock over a period of 110 days are recorded, and the summary descriptive statistics are given as follows: Descriptive Statistics: return Variable N N* Mean SE Mean StDev Minimum Q1 Median Q3 Maximum Return 110 0 0.000983 .00296 .03103 -.19992 -.01393 .00322 .01591 .09771 a) Find a 95% confidence interval estimate for μ, where μ is the population mean rate of return of the stock. b) Test the hypothesis Ho:μ= 0 versus Ha:μ > 0...
12. Below is a table detailing the number of days of personal travel over a year...
12. Below is a table detailing the number of days of personal travel over a year paired with annual household income (in 1000's of dollars) for 9 various families. HH Income ($000's) Travel Days 61 11 32 6 45 13 35 9 22 3 89 21 30 8 74 15 37 9 a. Construct a scatterplot for this data set in the region to the right (with household income as the independent variable, and travel days as the dependent variable.)...
For the 12 month period February 2018 through January 2019, the number of degree days that...
For the 12 month period February 2018 through January 2019, the number of degree days that accrued for the Amherst, MA area was 5903. Many houses in New England heat with oil. Suppose a reasonable-size house required a total of 1400 gallons of oil for that recent entire 12- month period. Suppose also that heating oil is priced at $2.90 per gallon. A. What was the total cost to purchase the oil to heat the house for the entire year?...
Below you will find the closing stock prices for eBay over a three-week period. Calculate the...
Below you will find the closing stock prices for eBay over a three-week period. Calculate the simple three-day and five-day moving averages for the stock. (Round your answers to 2 decimal places. Omit the "$" sign in your response.)    Date Close 4/23/2012 $ 37.18 4/24/2012 37.00 4/25/2012 36.60 4/26/2012 36.86 4/27/2012 36.12 4/30/2012 36.29 5/1/2012 36.36 5/2/2012 36.40 5/3/2012 37.09 5/4/2012 37.19 5/7/2012 37.12 5/8/2012 37.28 5/9/2012 37.61 5/10/2012 37.76 5/11/2012 37.59    3-day      5-day     4/23/2012 4/24/2012...
Below you will find the closing stock prices for eBay over a three-week period. Calculate the...
Below you will find the closing stock prices for eBay over a three-week period. Calculate the simple three-day and five-day moving averages for the stock. (Round your answers to 2 decimal places.) Week Day Close 1 Monday $37.31 Tuesday 37.13 Wednesday 36.73 Thursday 36.99 Friday 36.25 2 Monday 36.42 Tuesday 36.49 Wednesday 36.53 Thursday 37.22 Friday 37.32 3 Monday 37.25 Tuesday 37.41 Wednesday 37.74 Thursday 37.89 Friday 37.72 most of my answers were inncorrect please help!
Below you will find the closing stock prices for eBay over a three-week period. Calculate the...
Below you will find the closing stock prices for eBay over a three-week period. Calculate the simple three-day and five-day moving averages for the stock. (Round your answers to 2 decimal places.) Week Day Close 1 Monday $38.48 Tuesday 38.30 Wednesday 37.90 Thursday 38.16 Friday 37.42 2 Monday 37.59 Tuesday 37.66 Wednesday 37.70 Thursday 38.39 Friday 38.49 3 Monday 38.42 Tuesday 38.58 Wednesday 38.91 Thursday 39.06 Friday 38.89 Day 3day 5day 1 2 3 4 5 6 7 8 9...
Y is a Binomial random variable where, Y = The number of days in a week...
Y is a Binomial random variable where, Y = The number of days in a week someone goes to the gym. Where a week has 7 days and the probability of someone going to the gym on any given day is .65.  What is the probability that someone goes to the gym at least 3 days out of the week? Hint: This is a cumulative probability, so you need to add up the probabilities of Y equaling all the possible values...
The following are closing prices of Google stock for a sample of trading days. Use the...
The following are closing prices of Google stock for a sample of trading days. Use the 1-Var Stats command in the TI-84 PLUS calculator to compute the sample standard deviation. 455.21 , 482.37, 483.19, 459.63, 497.99, 475.10, 472.08, 444.95, 489.22 Write only a number as your answer. Round to two decimal places (for example 8.32). Your Answer:
Company Inventory Conversion Period, days Average Collection Period, days Payables Deferral Period, days Cash Conversion Cycle,...
Company Inventory Conversion Period, days Average Collection Period, days Payables Deferral Period, days Cash Conversion Cycle, days Adidas 112 27 57 82 Puma 107 18 49 Nike 128 20 43 105 Under Armor 89 24 21 1)calculate CCC for Puma and UA. 2)pick any 1 company of the 4: how its operational liquidity stands versus competitors (other 3 firms)? how can this company improve its liquidity? What are possible risks/limitations to your proposed changes?
The number of faults over a period of time was collected for a sample of 100...
The number of faults over a period of time was collected for a sample of 100 data transmission lines. We want to test if the data come from a Poisson distribution. number of faults 0 1 2 3 4 5 >5 number of lines 38 30 16 9 5 2 0 (a) Assuming the number of faults for a data-transmission line, Yi , i = 1, . . . , 100, follows a Poisson distribution with parameter λ, find the...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT