In: Computer Science
Write a program to insert the following elements into a hash table of size 17. The hash function is X mod 17 where X is the input element.
6, 12, 34, 29, 28, 11, 23, 7, 0, 33, 30, 45
Use linear probing to resolve any collisions.
Q-> Write a program to insert the following elements into a hash table of size 17. The hash function is X mod 17 where X is the input element.
6, 12, 34, 29, 28, 11, 23, 7, 0, 33, 30, 45
Hash table =
| 0 | |
| 1 | |
| 2 | |
| 3 | |
| 4 | |
| 5 | |
| 
 6  | 
6 | 
| 7 | |
| 8 | |
| 9 | |
| 10 | |
| 11 | |
| 12 | |
| 13 | |
| 14 | |
| 15 | |
| 16 | 
2. Insert 12: Index = 12 mod 17 = 12
Hash table =
| 0 | |
| 1 | |
| 2 | |
| 3 | |
| 4 | |
| 5 | |
| 
 6  | 
6 | 
| 7 | |
| 8 | |
| 9 | |
| 10 | |
| 11 | |
| 12 | 12 | 
| 13 | |
| 14 | |
| 15 | |
| 16 | 
3. Insert 34: Index = 34 mod 17 = 0
Hash table =
| 0 | 
 34  | 
| 1 | |
| 2 | |
| 3 | |
| 4 | |
| 5 | |
| 
 6  | 
6 | 
| 7 | |
| 8 | |
| 9 | |
| 10 | |
| 11 | |
| 12 | 12 | 
| 13 | |
| 14 | |
| 15 | |
| 16 | 
4. Insert 29: Index = 29 mod 17 = 12
Collision occurred, use linear probing, => index = 13
Hash table =
| 0 | 
 34  | 
| 1 | |
| 2 | |
| 3 | |
| 4 | |
| 5 | |
| 
 6  | 
6 | 
| 7 | |
| 8 | |
| 9 | |
| 10 | |
| 11 | |
| 12 | 12 | 
| 13 | 29 | 
| 14 | |
| 15 | |
| 16 | 
5. Insert 28: Index = 28 mod 17 = 11
Hash table =
| 0 | 
 34  | 
| 1 | |
| 2 | |
| 3 | |
| 4 | |
| 5 | |
| 
 6  | 
6 | 
| 7 | |
| 8 | |
| 9 | |
| 10 | |
| 11 | 28 | 
| 12 | 12 | 
| 13 | 29 | 
| 14 | |
| 15 | |
| 16 | 
6. Insert 11: Index = 11 mod 17 = 11
Collision occurred: => use linear probing,=> index = 12
again Collision occurred: => use linear probing,=> index = 13
again Collision occurred: => use linear probing,=> index = 14
Hash table =
| 0 | 
 34  | 
| 1 | |
| 2 | |
| 3 | |
| 4 | |
| 5 | |
| 
 6  | 
6 | 
| 7 | |
| 8 | |
| 9 | |
| 10 | |
| 11 | 28 | 
| 12 | 12 | 
| 13 | 29 | 
| 14 | 11 | 
| 15 | |
| 16 | 
7. Insert 23: Index = 23 mod 17 = 6
Collision occurred: => use linear probing,=> index = 7
Hash table =
| 0 | 
 34  | 
| 1 | |
| 2 | |
| 3 | |
| 4 | |
| 5 | |
| 
 6  | 
6 | 
| 7 | 23 | 
| 8 | |
| 9 | |
| 10 | |
| 11 | 28 | 
| 12 | 12 | 
| 13 | 29 | 
| 14 | 11 | 
| 15 | |
| 16 | 
8. Insert 7: Index = 7 mod 17 = 7
Collision occurred: => use linear probing,=> index = 8
Hash table =
| 0 | 
 34  | 
| 1 | |
| 2 | |
| 3 | |
| 4 | |
| 5 | |
| 
 6  | 
6 | 
| 7 | 23 | 
| 8 | 7 | 
| 9 | |
| 10 | |
| 11 | 28 | 
| 12 | 12 | 
| 13 | 29 | 
| 14 | 11 | 
| 15 | |
| 16 | 
9. Insert 0: Index = 0 mod 17 = 0
Collision occurred: => use linear probing,=> index = 1
Hash table =
| 0 | 
 34  | 
| 1 | 0 | 
| 2 | |
| 3 | |
| 4 | |
| 5 | |
| 
 6  | 
6 | 
| 7 | 23 | 
| 8 | 7 | 
| 9 | |
| 10 | |
| 11 | 28 | 
| 12 | 12 | 
| 13 | 29 | 
| 14 | 11 | 
| 15 | |
| 16 | 
10. Insert 33: Index = 33 mod 17 = 16
Hash table =
| 0 | 
 34  | 
| 1 | 0 | 
| 2 | |
| 3 | |
| 4 | |
| 5 | |
| 
 6  | 
6 | 
| 7 | 23 | 
| 8 | 7 | 
| 9 | |
| 10 | |
| 11 | 28 | 
| 12 | 12 | 
| 13 | 29 | 
| 14 | 11 | 
| 15 | |
| 16 | 33 | 
11. Insert 30: Index = 30 mod 17 = 13
Collision occurred: => use linear probing,=> index = 14
Collision occurred: => use linear probing,=> index = 15
Hash table =
| 0 | 
 34  | 
| 1 | 0 | 
| 2 | |
| 3 | |
| 4 | |
| 5 | |
| 
 6  | 
6 | 
| 7 | 23 | 
| 8 | 7 | 
| 9 | |
| 10 | |
| 11 | 28 | 
| 12 | 12 | 
| 13 | 29 | 
| 14 | 11 | 
| 15 | 30 | 
| 16 | 33 | 
12. Insert 45: Index = 45 mod 17 = 11
next free index is 2 using linear probing
Final Hash table =
| 0 | 
 34  | 
| 1 | 0 | 
| 2 | 45 | 
| 3 | |
| 4 | |
| 5 | |
| 
 6  | 
6 | 
| 7 | 23 | 
| 8 | 7 | 
| 9 | |
| 10 | |
| 11 | 28 | 
| 12 | 12 | 
| 13 | 29 | 
| 14 | 11 | 
| 15 | 30 | 
| 16 | 33 |