In: Chemistry
The Ksp value for bismuth sulfide (Bi2S3) is 2.0 × 10-40 at a given temperature, calculate the solubility in g/L
Bi2S3 -------------------> 2Bi^3+ (aq) + 3S^2- (aq)
2s 3s
Ksp = [Bi^3+]^2[S^2-]^3
2*10^-40 = (2s)^2*(3s)^3
2*10^-40 = 4s^2*27s^3
2*10^-40 = 108s^5
s^5 = 0.0185*10^-40
s = 0.45*10^-8
s = 4.5*10^-9M
solubility = 4.5*10^-9 mole/L
molar mass of Bi2S3 = 514.15g/mole
solubility = 4.5*10^-9 mole/L * 514.15g/mole
= 2.3*10^-6 g/L >>>>answer