In: Chemistry
The Ksp of calicium carbonate CoCO3, is 1.00x 10 ^-10. Calculate the solubility of this compound in g/L
CaCO3 -----------------------> Ca^2+ (aq) + CO3^2-
s s
Ksp = [Ca^2+][CO3^2-]
1*10^-10 = s*s
s^2 = 1*10^-10
s = 1*10^-5
solubility of CaCO3 = 1*10^-5 mole/l
molar mass of CaCO3 = 100g/mole
solubility of CaCo3 = 1*10^-5 mole/L *100g/mole
= 10^-3 g/L >>>>answer