In: Statistics and Probability
A poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years age. Five years age, a sample of 270 students showed that 120 considered themselves overweight. This year a poll of 300 students showed that 140 considered themselves overweight. At a 5% level of significance, test to see if there is any difference in the proportion of college students who consider themselves overweight between the two polls. What is your conclusion?
Data:
n1 = 270
n2 = 300
p1 = 0.444444444
p2 = 0.466666667
Hypotheses:
Ho: p1 = p2
Ha: p1 ≠ p2
Decision Rule:
α = 0.05
Lower Critical z- score = -1.959963985
Upper Critical z- score = 1.959963985
Reject Ho if |z| > 1.959963985
Test Statistic:
Average proportion, p = (n1p1 + n2p2)/(n1 + n2) = (270 * 0.444444444444444 + 300 * 0.466666666666667)/(270 + 300) = 0.456140351
q = 1 - p = 1 - 0.456140350877193 = 0.543859649
SE = √[pq * {(1/n1) + (1/n2)}] = √(0.456140350877193 * 0.543859649122807 * ((1/270) + (1/300))) = 0.041781842
z = (p1 - p2)/SE = (0.444444444444444 - 0.466666666666667)/0.0417818421149385 = -0.531863151
p- value = 0.59482078
Decision (in terms of the hypotheses):
Since 0.531863151 < 1.959963985 we fail to reject Ho
Conclusion (in terms of the problem):
There is no sufficient evidence of a significant difference between the proportions.
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