Question

In: Statistics and Probability

A poll was taken this year asking college students if they considered themselves overweight. A similar...

A poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years age. Five years age, a sample of 270 students showed that 120 considered themselves overweight. This year a poll of 300 students showed that 140 considered themselves overweight. At a 5% level of significance, test to see if there is any difference in the proportion of college students who consider themselves overweight between the two polls. What is your conclusion?

Solutions

Expert Solution

Data:    

n1 = 270   

n2 = 300   

p1 = 0.444444444   

p2 = 0.466666667   

Hypotheses:    

Ho: p1 = p2    

Ha: p1 ≠ p2    

Decision Rule:    

α = 0.05   

Lower Critical z- score =   -1.959963985

Upper Critical z- score = 1.959963985

Reject Ho if |z| >   1.959963985

Test Statistic:    

Average proportion, p = (n1p1 + n2p2)/(n1 + n2) = (270 * 0.444444444444444 + 300 * 0.466666666666667)/(270 + 300) = 0.456140351

q = 1 - p = 1 - 0.456140350877193 = 0.543859649

SE = √[pq * {(1/n1) + (1/n2)}] = √(0.456140350877193 * 0.543859649122807 * ((1/270) + (1/300))) = 0.041781842

z = (p1 - p2)/SE = (0.444444444444444 - 0.466666666666667)/0.0417818421149385 = -0.531863151

p- value = 0.59482078   

Decision (in terms of the hypotheses):    

Since 0.531863151 < 1.959963985 we fail to reject Ho

Conclusion (in terms of the problem):    

There is no sufficient evidence of a significant difference between the proportions.

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