9. In the crystal structure of CsCl, the distance between Cs+ and Cl is equal to...

9. In the crystal structure of CsCl, the distance between Cs+ and Cl is equal to 3.55 Å (0.355 nm). Calculate density of CsCl (in g/cm3 ).

Expert Solution

We know density , d = (Z x atomic mass) / ( No x a³ x 10^-30 cm³ )

Where Z = No . of atoms in a unit cell = 1 Since it is a simple cubic structure

atomic mass of CsCl = 168.36 g

N_o = avagadro number = 6.023x10²³

a = edge length = 0.355 nm = 0.355x10^-9 m = 355x10^-12 m = 355 pm

Plug the values we get d = (Z x atomic mass) / ( No x a³ x 10^-30 cm³ )

= (1 x 168.36) / ( 6.023x10²³ x 355³ x 10^-30 cm³ )

= 6.25 g/cm³

Therefore the density of CsCl is 6.25 g/cm³

queen_honey_blossom answered 9 months ago

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