In: Physics
1)What is the force between two equal charges (1 Coulomb) that are separated by a distance of 1 km? 2)Suppose that the charge of one of the charges in problem #1 is reduced to half of its original value. How does the new force compare to the original force?
1)
Force between two charges is calculated by Coulomb's Law.
Here,
is force between two charges
and
separated by distance
and
is Coulomb's constant.
Substitute 1 C for
&
, 1000 m for
and
for
in above equation of force.
N
2)
Let value of charge of
be reduced to half and it becomes
.
Here,
is force between two charges
and
separated by distance
.
Substitute 1 C for
, 0.5 C for
,
1000 m for
and
for
in above equation of force.
N
Thus, when the charge of one of the charges is reduced to half of its original value, force will also be reduced to half.