In: Statistics and Probability
Construct a confidence interval of the population proportion at the given level of confidence. x equals x= 120 120, n equals n= 1100 1100, 90 90% confidence
x = | 120 | |||
sample size | n = | 1100 | ||
sample proportion p̂ | x/n= | 0.1091 | ||
std error =Se | =√(p*(1-p)/n) = | 0.0094 | ||
for 90 % CI value of z= | 1.6449 | |||
margin of error E=z*std error = | 0.0155 | |||
lower confidence bound=sample proportion-margin of error | 0.0936 | |||
Upper confidence bound=sample proportion+margin of error | 0.1246 |