In a large survey, third graders were asked what their favorite color is. The results are in the table below.

Suppose that 10 randomly selected students are chose. What is the probability that 3 students say blue is their favorite color?

The distribution of actual weights of 80 ounces wedges of cheddar Cheese produced at a dairy is Normal with mean 8.1 ounce and standard deviation is 0.1 ounce. If there is only a 5% chance that the average weight of the sample of five of the cheese wedges will be below ___________ ( get the sample mean value to 2 decimals)

z score:    Answer format: #.##

Average Weight:    Answer format: #.##

The serum cholesterol levels in men aged 18 – 24 are normally distributed with a mean of 178.1 and a standard deviation of 40.7. Units are in mg/100mL. Use R. Paste your commands and output into the answer box.

a) If a man aged 18 – 24 is randomly selected, find the probability that his serum cholesterol level is between 170 and 200.

b) If a sample of 10 men aged 18 – 24 is randomly selected, find the probability that their mean serum cholesterol level is between 180 and 190.

Direct mail advertisers send solicitations​ ("junk mail") to thousands of potential customers in the hope that some will buy the​ company's product. The response rate is usually quite low. Suppose a company wants to test the response to a new flyer and sends it to 1110 people randomly selected from their mailing list of over​ 200,000 people. They get orders from 108 of the recipients.

​Create a 90% confidence interval for the percentage of people the company contacts who may buy something.

( __ % __ % )

​(Round to one decimal place as​ needed.)

Answer the following application exercise on organization and visualization of data.
1. You can use Excel.
2. If you use the calculator and perform the exercise manually, obtain a photo of the process performed using the clipping and search of your result in Word.
3. Remember to include presentation sheet in APA format.
A sample of 30 employees who work investigating cases of possible money laundering, answers a survey about the average time in days we take them analyzes, present findings and recommendations. Next, your answers are detailed
25 22 20 16 13 16 32 26 13 24 15 15 14 14 54 11 24 24 24 19 17 10 16 48 11 13 20 13 12 24
Summary of this data:
1. Building a frequency distribution table.
2. Building graphical representations: histogram, frequency polygon and warhead.
3. Calculating the measures of central tendency: mean, mode and median.
4. Make a comment on what the data related to the average time of days to solve each case indicate.

1. You’re a beer brewer and you’re interested in whether there is a relationship between the weight of grains used to brew the beer, and the percent alcohol of the beer. You record your data below of your homebrew. (3 points)

1. What kind of statistical test will you be performing?

2. Will you need to test for equal variance? If so, what are your results and how does that influence the next steps in your analysis?

3. What are your null and alternative hypotheses?

H₀:

H_A:

4. Discuss the results of your analysis. Will you accept or reject your null hypothesis? Why? What can you specifically say about the data?

Given a normal distribution with μ equals=102 and σ equals= 25​, and given you select a sample of n equals 25

d) There is a 69​% chance that Upper X is above what​ value?

(Type an integer or decimal rounded to two decimal places as​ needed.)

The following data represent crime rates per 1000 population for a random sample of 46 Denver neighborhoods.† 63.2 36.3 26.2 53.2 65.3 32.0 65.0 66.3 68.9 35.2 25.1 32.5 54.0 42.4 77.5 123.2 66.3 92.7 56.9 77.1 27.5 69.2 73.8 71.5 58.5 67.2 78.6 33.2 74.9 45.1 132.1 104.7 63.2 59.6 75.7 39.2 69.9 87.5 56.0 154.2 85.5 77.5 84.7 24.2 37.5 41.1 (a) Use a calculator with mean and sample standard deviation keys to find the sample mean x and sample standard deviation s. (Round your answers to one decimal place.) x = crimes per 1000 people s = crimes per 1000 people (b) Let us say the preceding data are representative of the population crime rates in Denver neighborhoods. Compute an 80% confidence interval for μ, the population mean crime rate for all Denver neighborhoods. (Round your answers to one decimal place.) lower limit crimes per 1000 people upper limit crimes per 1000 people (c) Suppose you are advising the police department about police patrol assignments. One neighborhood has a crime rate of 62 crimes per 1000 population. Do you think that this rate is below the average population crime rate and that fewer patrols could safely be assigned to this neighborhood? Use the confidence interval to justify your answer. Yes. The confidence interval indicates that this crime rate is below the average population crime rate. Yes. The confidence interval indicates that this crime rate does not differ from the average population crime rate. No. The confidence interval indicates that this crime rate is below the average population crime rate. No. The confidence interval indicates that this crime rate does not differ from the average population crime rate. (d) Another neighborhood has a crime rate of 76 crimes per 1000 population. Does this crime rate seem to be higher than the population average? Would you recommend assigning more patrols to this neighborhood? Use the confidence interval to justify your answer. Yes. The confidence interval indicates that this crime rate does not differ from the average population crime rate. Yes. The confidence interval indicates that this crime rate is higher than the average population crime rate. No. The confidence interval indicates that this crime rate is higher than the average population crime rate. No. The confidence interval indicates that this crime rate does not differ from the average population crime rate. (e) Compute a 95% confidence interval for μ, the population mean crime rate for all Denver neighborhoods. (Round your answers to one decimal place.) lower limit crimes per 1000 people upper limit crimes per 1000 people (f) Suppose you are advising the police department about police patrol assignments. One neighborhood has a crime rate of 62 crimes per 1000 population. Do you think that this rate is below the average population crime rate and that fewer patrols could safely be assigned to this neighborhood? Use the confidence interval to justify your answer. Yes. The confidence interval indicates that this crime rate is below the average population crime rate. Yes. The confidence interval indicates that this crime rate does not differ from the average population crime rate. No. The confidence interval indicates that this crime rate is below the average population crime rate. No. The confidence interval indicates that this crime rate does not differ from the average population crime rate. (g) Another neighborhood has a crime rate of 76 crimes per 1000 population. Does this crime rate seem to be higher than the population average? Would you recommend assigning more patrols to this neighborhood? Use the confidence interval to justify your answer. Yes. The confidence interval indicates that this crime rate does not differ from the average population crime rate. Yes. The confidence interval indicates that this crime rate is higher than the average population crime rate. No. The confidence interval indicates that this crime rate is higher than the average population crime rate. No. The confidence interval indicates that this crime rate does not differ from the average population crime rate. (h) In previous problems, we assumed the x distribution was normal or approximately normal. Do we need to make such an assumption in this problem? Why or why not? Hint: Use the central limit theorem. Yes. According to the central limit theorem, when n ≥ 30, the x distribution is approximately normal. Yes. According to the central limit theorem, when n ≤ 30, the x distribution is approximately normal. No. According to the central limit theorem, when n ≥ 30, the x distribution is approximately normal. No. According to the central limit theorem, when n ≤ 30, the x distribution is approximately normal.

use DMAIC to improve a process in one or more of the organizations listed below:

Health-care facility

the NIH wants to prove that taking daily asprine reduce the chance of second heart attack with in five years. wiyhout taking the asprine it is known that 35% OF will suffer a second attack with in 5 years. it is decide to use a level of significance of 0.05 a total 225patients particepated by the taking daily asprien following their first heart attack. of those 45 had a second attack within 5 years

a, state the null and alternative haypothesis

b, what is the Z_crit

C,what is Z data

d, do you reject the null hypothesis?

e, state your conclusion using words in the pronlame

Calculate the following confidence intervals. The male confidence interval would be one calculation in the spreadsheet and the females would be a second calculation.  Mean for Females 7.666 and Standard Deviation 1.878. Mean for Males 7.764 and Standard Deviation 1.855. Total Males 17 and Total Females 18.  

1. Give and interpret the 95% confidence intervals for males and a second 95% confidence interval for females on the SLEEP variable. Which is wider and why?
2. Give and interpret the 99% confidence intervals for males and a second 99% confidence interval for females on the SLEEP variable. Which is wider and why?

All but the "face" cards (Kings, Queens, Jacks) have been removed from a regular deck of 52 playing cards

Draw two cards at random, without replacement. What is the probability that both cards are "Spades"? (Write answer as a fraction reduced to lowest terms) ___________

Based on your answer above, what are the Odds Against both cards being "Spades"? __________

Now draw a third card, again without replacement. What is the probability that this third card is a "Spade" GIVEN that NEITHER of the first two cards drawn are "Spades"? _____________

What would be your answer to the first question asked in this problem if the drawing had been done WITh replacement? ____________

Using diaries for many weeks, a study on the lifestyles of visually impaired students was conducted. The students kept track of many lifestyle variables including how many hours of sleep obtained on a typical day. Researchers found that visually impaired students averaged 9.63 hours of sleep, with a standard deviation of 2.92 hours. Assume that the number of hours of sleep for these visually impaired students is normally distributed.

(a) What is the probability that a visually impaired student gets at most 6.3 hours of sleep? Express your answer as a percent rounded to 2 decimal places. e.g. 1.23% Do not include the % symbol in your answer.

(b) What is the probability that a visually impaired student gets between 8 and 9.02 hours of sleep? Express your answer as a percent rounded to 2 decimal places. e.g. 1.23% Do not include the % symbol in your answer.

(c) What is the probability that a visually impaired student gets at least 8.2 hours of sleep? Express your answer as a percent rounded to 2 decimal places. e.g. 1.23% Do not include the % symbol in your answer.

(d) What is the sleep time that cuts off the top 33 % of sleep hours? Round your answer to 2 decimal places.

(e) If 400 visually impaired students were studied, how many students would you expect to have sleep times of more than 9.02 hours? Round to the nearest whole number.

(f) A school district wants to give additional assistance to visually impaired students with sleep times at the first quartile and lower. What would be the maximum sleep time to be recommended for additional assistance? Round your answer to 2 decimal places.

Assuming the probabilities of alternative prices for GM yellow corn are as stated in Exhibit 4,
calculate the expected change in profits from adopting our recommendation. (This is important since
it can be used to justify our consulting fees.)

Exhibit 4: Marketing and Price Analysis

Mercer Farms Group - Marketing Division

Background: The Marketing Division was asked to analyze the expected prices and probabilities for AA yellow corn and Genetically Modified (GM) yellow corn for the summer harvest.

Analysis: Estimating the future demand and supply of the commodity derives the projected market prices. The factors considered in the demand portion of this analysis include population growth, consumer preferences, and income. Relative prices of substitutes and complements were considered as static or unchanged. The supply portion of the analysis considered current input prices, existing technology, existing stocks on hand (domestic and foreign), and government policies (domestic and foreign). Exchange rate estimates were taken from our International Division’s current forecast.

Price Forecast:

AA Yellow Corn (domestic): Price per bushel: $ 5.00.

GM Yellow Corn (domestic):

Two alternative price scenarios should be considered. The demand acceptance of GM products in general is in question. There have been numerous reviews by governments all over the world, but particularly in Europe.

Scenario #1: Price of GM Yellow Corn (domestic): $ 5.50. Europe adopts few restrictions on the importation of GM products, but prohibits European production.

Scenario #2: Price of GM Yellow Corn (domestic): $ 4.70. Europe adopts heavy restrictions on the importation of GM products.

At this time, we consider the probabilities to be: Scenario #1: 60%; and Scenario #2: 40%.

The futures markets will have determined which price will occur before it is time to plant the summer crop.

he average daily dietary fiber intake was 16 grams per day. You believe that the average daily dietary fiber intake differs from 16 grams per day. What are the appropriate null and alternative hypotheses? Question 9 options: A) vs B) vs C) vs D) vs E) vs