Provide an example of where you could use correlation in real life. Explain why a t-test is necessary before you accept this correlation as being real in the population.

"Please give extreme step by step actions on how to explain this, so that I can understand to explain to class".

What is the purpose of Reverse testing? (select all that apply)

how do we interpret how typical a score is compare to the population based on the population mean and standard deviation

You wish to test the following claim (HaHa) at a significance level of α=0.005α=0.005.

Ho:μ1=μ2Ho:μ1=μ2
Ha:μ1<μ2Ha:μ1<μ2

You believe both populations are normally distributed, but you do not know the standard deviations for either. And you have no reason to believe the variances of the two populations are equal You obtain a sample of size n1=10n1=10 with a mean of ¯x1=70.4x¯1=70.4 and a standard deviation of s1=5.5s1=5.5 from the first population. You obtain a sample of size n2=13n2=13 with a mean of ¯x2=91x¯2=91 and a standard deviation of s2=19.1s2=19.1 from the second population.

1. What is the test statistic for this sample?
   
   test statistic =  Round to 3 decimal places.
   
2. What is the p-value for this sample? For this calculation, use .
   
   p-value =  Use Technology Round to 4 decimal places.
   
3. The p-value is...
   • less than (or equal to) αα
   • greater than αα
   
   
4. This test statistic leads to a decision to...
   • reject the null
   • accept the null
   • fail to reject the null
   
   
5. As such, the final conclusion is that...
   • There is sufficient evidence to warrant rejection of the claim that the first population mean is less than the second population mean.
   • There is not sufficient evidence to warrant rejection of the claim that the first population mean is less than the second population mean.
   • The sample data support the claim that the first population mean is less than the second population mean.
   • There is not sufficient sample evidence to support the claim that the first population mean is less than the second population mean.

You wish to test the claim that the first population mean is not equal to the second population mean at a significance level of α=0.005α=0.005.     

Ho:μ1=μ2Ho:μ1=μ2
Ha:μ1≠μ2Ha:μ1≠μ2

You obtain the following two samples of data.

1. What is the test statistic for this sample?
   
   test statistic =  Round to 3 decimal places.
   
2. What is the p-value for this sample?
   
   p-value =  Use Technology Round to 4 decimal places.
   
3. The p-value is...
   • less than (or equal to) αα
   • greater than αα
   
   
4. This test statistic leads to a decision to...
   • reject the null
   • accept the null
   • fail to reject the null
   
   
5. As such, the final conclusion is that...
   • There is sufficient evidence to warrant rejection of the claim that the first population mean is not equal to the second population mean.
   • There is not sufficient evidence to warrant rejection of the claim that the first population mean is not equal to the second population mean.
   • The sample data support the claim that the first population mean is not equal to the second population mean.
   • There is not sufficient sample evidence to support the claim that the first population mean is not equal to the second population mean.

A psychologist specializing in marriage counseling claims that, among all married couples, the proportion p for whom her communication program can prevent divorce is at least 77%. In a random sample of 240 married couples who completed her program, 176 of them stayed together. Based on this sample, can we reject the psychologist's claim at the 0.05 level of significance?Perform a one-tailed test. Then fill in the table below.Carry your intermediate computations to at least three decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.)

A scientific study on speed limits gives the following data table.

Using technology, it was determined that the total sum of squares (SST) was 4029.2, the sum of squares regression (SSR) was 3968.4, and the sum of squares due to error (SSE) was 60.835. Calculate R2 and determine its meaning. Round your answer to four decimal places.

Select the correct answer below:

R2=0.0153

Therefore, 1.53% of the variation in the observed y-values can be explained by the estimated regression equation.

R2=0.9849

Therefore, 98.49% of the variation in the observed y-values can be explained by the estimated regression equation.

R2=0.0151

Therefore, 1.51% of the variation in the observed y-values can be explained by the estimated regression equation.

R2=1.0153

Therefore, 10.153% of the variation in the observed y-values can be explained by the estimated regression equation.

For each of the research studies described below, select which of the following analyses would be most appropriate. Please type your answers in the boxes exactly as they are printed here. I will check to see if Bb scored you “incorrect” for misspellings/typos, but if you type carefully (or copy-paste carefully), I can get grades done more quickly.

YOUR ANSWER CHOICES:

single sample t-test

independent samples t-test

related samples t-test

one-way independent measures ANOVA

one-way repeated measures ANOVA

Scheffe’s test

Tukey’s HSD test

two-way two-factor independent samples ANOVA

two-way mixed design ANOVA

Pearson correlation

one-way goodnesss of fit chi-square

two-way chi-square test for independence

linear regression.

The RESEARCH STUDIES:

a. Ten PSY, ten PT, and ten NSG students in a statistics course are selected at random and asked to estimate the number hours per week they are spending on the statistics course. The researcher wants to determine whether the three types of majors spend different amounts of time, on average, studying statistics. The statistical test to use would be _________________ .

b. People who are self-identified as either lower, working, middle, or upper class are compared on their attitudes toward corporal punishment of children. Attitudes are measured on a 7-point scale ranging from strongly disagree with the practice (1) to strongly agree with the practice (7). The statistical test to use would be ____________.

c. The effectiveness of a sexual harassment program is tested by taking before and after measures of sexual harassment knowledge. The knowledge scale is a 100-point scale, with higher scores indicating greater knowledge. The statistical test to use would be ___________.

d. A random sample of 100 CSS students is asked to write down their GPA and the number of hours they work per week for a salary. The researcher (the head of the Student Development Center) wants to determine whether there is a relationship between the number of hours worked and GPA. The statistical test to use would be_______________ .

e. PSY, PT, and NSG majors at CSS are asked to label the workload in their major as “light,” “average,” or “excessive.” The researcher (the chair of the Nursing Department) wants to find out if there is a greater likelihood (or frequency) of NSG majors selecting “excessive” than the other majors. The statistical test to use would be ______________.

f. A researcher wants to determine whether the average height of a sample of adult American men with Klinefleter’s syndrome (M = 5’11”) differs from the average height of adult American Men (population μ is 5’8”, σ is not known). The statistical test to use would be ______

g. A researcher wants to predict marital satisfaction scores from conflict resolution strategies, length of the marital relationship, and number of extramarital affairs. The statistical test to use would be__________ .

h. Eight MGT, eight HIM, and eight PSY students who had completed Dr. Dietrich’s statistics course were selected at random and given one of two types of statistics exam, open-book or closed-book. The researcher wants to determine whether there is an effect of major and type of exam on the mean number of correct answers. The statistical test to use would be ___________.

A researcher is interested in whether the variation in the size of human beings is proportional throughout each part of the human. To partly answer this question they looked at the correlation between the foot length (in millimeters) and height (in centimeters) of 30 randomly selected adult males. The data is provided below. Use Excel to calculate the correlation coefficient r between the two data sets. Round your answer to two decimal places.

Foot length (mm)   Height (cm)
244.9   159.2
248.5   164.8
248.1   173.7
252.3   171.7
251.6   164.6
256.5   171.4
240.3   179.7
252.7   183.1
259.7   183.2
263.3   177.9
245.7   181.6
261.0   172.9
256.6   185.2
256.0   169.6
254.7   169.0
248.1   177.6
255.9   181.9
259.4   180.4
277.6   173.0
287.7   175.0
281.2   189.6
269.0   174.1
288.4   176.1
281.8   189.7
289.1   182.7
283.2   186.0
292.5   177.8
285.4   187.7
287.5   190.5
276.8   194.1

R=

5.A survey of 15 randomly selected employees from Bob’s factory was taken to find out how many sick days they took due to colds and flu last year. Suppose Bob didn’t take a random sample. Suppose the employees in the sample were those who responded to an advertisement Bob put out to the whole company, looking for volunteers to participate in the survey. What kind of error would be made here? THERE IS ONLY ONE CORRECT ANSWER – CHECK YOUR LECTURE NOTES.

a.Undercoverage

b.Nonresponse

c.Bias due to a self-selected sample

d.None of the above

6.A statistics student wants to know what OSU students think about parking on campus. To obtain a sample of 20 students, he knocks on the doors of residents in his dorm until he finds 20 people home who can take his survey about parking. This is a:

a.Simple random sample

b.Stratified sample

c.Convenience sample

Question 12 (1 point)

The coefficient of determination for the above bivariate data is:

Question 12 options:

A survey of several 9 to 11 year olds recorded the following amounts spent on a trip to the mall: $20.70, $20.82, $12.32, $19.53, $24.43

Construct the 98% confidence interval for the average amount spent by 9 to 11 year olds on a trip to the mall. Assume the population is approximately normal.

Step 1 of 4: Calculate the sample mean for the given sample data. Round your answer to two decimal places.

Step 2 of 4: Calculate the sample standard deviation for the given sample data. Round your answer to two decimal places.

Step 3 of 4: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.

Step 4 of 4: Construct the 98% confidence interval. Round your answer to two decimal places.

The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is registered to vote. Suppose that 608 employed persons and 719 unemployed persons are independently and randomly selected, and that 318 of the employed persons and 269 of the unemployed persons have registered to vote. Can we conclude that the percentage of employed workers ( p1 ), who have registered to vote, exceeds the percentage of unemployed workers ( p2 ), who have registered to vote? Use a significance level of α=0.01 for the test.

Step 1 of 6: State the null and alternative hypotheses for the test.

Step 2 of 6: Find the values of the two sample proportions, pˆ1p^1 and pˆ2p^2. Round your answers to three decimal places.

Step 3 of 6: Compute the weighted estimate of p, p‾p‾. Round your answer to three decimal places.

Step 4 of 6: Compute the value of the test statistic. Round your answer to two decimal places.

Step 5 of 6: Determine the decision rule for rejecting the null hypothesis H0H0. Round the numerical portion of your answer to two decimal places.

Step 6 of 6: Make the decision for the hypothesis test.

Q) Let Xbe a discrete random variable representing the maximum value of the two numbers on