What price do farmers get for their watermelon crops? In the third week of July, a random sample of 40 farming regions gave a sample mean of x = $6.88 per 100 pounds of watermelon. Assume that σ is known to be $1.92 per 100 pounds.
(a) Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their watermelon crop. What is the margin of error? (Round your answers to two decimal places.)
| lower limit | $ |
| upper limit | $ |
| margin of error | $ |
(b) Find the sample size necessary for a 90% confidence level with
maximal error of estimate E = 0.43 for the mean price per
100 pounds of watermelon. (Round up to the nearest whole
number.)
farming regions
(c) A farm brings 15 tons of watermelon to market. Find a 90%
confidence interval for the population mean cash value of this
crop. What is the margin of error? Hint: 1 ton is 2000
pounds. (Round your answers to two decimal places.)
| lower limit | $ |
| upper limit | $ |
| margin of error | $ |
In: Math
5.30 A concern to public health officials is whether a
concentration of lead in the paint of older
homes may have an effect on the muscular development of young
children. In order to evaluate
this phenomenon, a researcher exposed 90 newly born mice to paint
containing a specified
amount of lead. The number of Type 2 fibers in the skeletal muscle
was determined 6 weeks
after exposure. The mean number of Type 2 fibers in the skeletal
muscles of normal mice of this
age is 21.7. The n=90 mice yielded y(mean)=8.8, s=15.3. Is there
significant evidence in the data
to support the hypothesis that the mean number of Type 2 fibers is
different from 21.7 using an
alpha = .05 test?
Question: How to run in R?
In: Math
Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma.† Over a period of months, an adult male patient has taken thirteen blood tests for uric acid. The mean concentration was x = 5.35 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with σ = 1.81 mg/dl.
(a) Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of error? (Round your answers to two decimal places.)
| lower limit | |
| upper limit | |
| margin of error |
(b) What conditions are necessary for your calculations? (Select
all that apply.)
n is largeuniform distribution of uric acidσ is unknownnormal distribution of uric acidσ is known
(c) Interpret your results in the context of this problem.
There is a 5% chance that the confidence interval is one of the intervals containing the population average uric acid level for this patient.The probability that this interval contains the true average uric acid level for this patient is 0.95. There is not enough information to make an interpretation.The probability that this interval contains the true average uric acid level for this patient is 0.05.There is a 95% chance that the confidence interval is one of the intervals containing the population average uric acid level for this patient.
(d) Find the sample size necessary for a 95% confidence level with
maximal margin of error E = 1.02 for the mean
concentration of uric acid in this patient's blood. (Round your
answer up to the nearest whole number.)
blood tests
In: Math
What is the value of research in your everyday life and when you are completing a graduate degree?
In: Math
Table 6
Sample No. X1 X2 X3
1 0.0629 0.0636 0.0640
2 0.0630 0.0631 0.0622
3 0.0628 0.0631 0.0633
4 0.0634 0.0630 0.0631
5 0.0619 0.0628 0.0630
6 0.0613 0.0629 0.0634
7 0.0630 0.0639 0.0625
8 0.0628 0.0627 0.0623
9 0.0623 0.0627 0.0633
10 0.0631 0.0631 0.0633
11 0.0635 0.0630 0.0638
12 0.0623 0.0630 0.0630
13 0.0635 0.0631 0.0630
14 0.0645 0.0640 0.0631
15 0.0619 0.0644 0.0632
16 0.0631 0.0627 0.0630
17 0.0616 0.0623 0.0631
18 0.0630 0.0630 0.0626
19 0.0636 0.0631 0.0629
20 0.0640 0.0635 0.0629
21 0.0628 0.0625 0.0616
22 0.0615 0.0625 0.0619
23 0.0630 0.0632 0.0630
24 0.0635 0.0629 0.0635
25 0.0623 0.0629 0.0630In: Math
Let x be a random variable that represents white blood cell count per cubic milliliter of whole blood. Assume that x has a distribution that is approximately normal, with mean μ = 6150 and estimated standard deviation σ = 2750. A test result of x < 3500 is an indication of leukopenia. This indicates bone marrow depression that may be the result of a viral infection.
(a) What is the probability that, on a single test, x
is less than 3500? (Round your answer to four decimal
places.)
(b) Suppose a doctor uses the average x for two tests
taken about a week apart. What can we say about the probability
distribution of x?
The probability distribution of x is approximately normal with μx = 6150 and σx = 2750.The probability distribution of x is approximately normal with μx = 6150 and σx = 1944.54. The probability distribution of x is approximately normal with μx = 6150 and σx = 1375.00.The probability distribution of x is not normal.
What is the probability of x < 3500? (Round your answer
to four decimal places.)
(c) Repeat part (b) for n = 3 tests taken a week apart.
(Round your answer to four decimal places.)
(d) Compare your answers to parts (a), (b), and (c). How did the
probabilities change as n increased?
The probabilities increased as n increased.The probabilities decreased as n increased. The probabilities stayed the same as n increased.
If a person had x < 3500 based on three tests, what
conclusion would you draw as a doctor or a nurse?
It would be a common event for a person to have two or three tests below 3,500 purely by chance. The person probably has leukopenia.It would be a common event for a person to have two or three tests below 3,500 purely by chance. The person probably does not have leukopenia. It would be an extremely rare event for a person to have two or three tests below 3,500 purely by chance. The person probably does not have leukopenia.It would be an extremely rare event for a person to have two or three tests below 3,500 purely by chance. The person probably has leukopenia.
In: Math
Two critics rate the service at six award-winning restaurants on a continuous 0 to 10 scale. Their rankings are shown in the table below. Restaurant 1 2 3 4 5 6 Critic 1: 6.1 5.2 8.9 7.4 4.3 9.7 Critic 2: 7.3 5.5 9.1 7.0 5.1 9.8
a) Is this paired or unpaired data?
b) Compute a 95% confidence interval for the mean difference in rating. Show all your working.
c) Is there a difference between the critics’ ratings, allowing for some random variation? Answer this question using a parametric hypothesis test, and compare your result to the confidence interval from part b.
d) Use a nonparametric hypothesis test to further investigate whether there is a difference between the critics’ rankings.
e) Is the parametric or non-parametric test more appropriate here?
In: Math
A worker has asked her supervisor for a confidential letter of recommendation for a new job. She estimates that there is an 80% chance that she will get the job if she receives a strong recommendation, a 40% chance if she receives a moderately good recommendation, and a 10% if she receives a weak recommendation. She further estimates that the probabilities that the recommendation will be strong, moderate and weak are 0.6, 0.3 and 0.1 respectively. Given that she fails to get the job, what is the probability that she received a weak recommendation?
In: Math
| Healthy | AOAUD |
| 10.82 | 9.32 |
| 10.71 | 8.73 |
| 10.56 | 8.46 |
| 10.49 | 8.46 |
| 10.30 | 8.42 |
| 9.49 | 8.23 |
| 9.32 | 8.12 |
| 9.25 | 8.09 |
| 9.20 | 7.97 |
| 9.08 | 7.82 |
| 9.06 | 7.05 |
| 9.02 | 6.63 |
| 8.98 | |
| 8.77 | |
| 8.77 | |
| 8.72 | |
| 8.60 | |
| 8.45 | |
| 8.40 | |
| 8.04 | |
| 7.92 | |
| 7.93 | |
| 7.87 | |
| 6.47 |
1. Assume that the mean adjusted hippocampal volume for healthy adolescents is 9.01 cubic centimeters. State the hypotheses to test whether the AOAUD mean hippocampal volume is less than this value.
To perform the hypothesis test, we will compute H0: m = 9.01 and HA: m < 9.01. By doing this, we get the results:
Hypothesis test results:
|
Variable |
Sample Mean |
Std. Err. |
DF |
T-Stat |
P-value |
|---|---|---|---|---|---|
|
var1 |
9.0091667 |
0.21260711 |
23 |
-0.003919593 |
0.4985 |
2. Compute the t-value and the P-value for this test.
?
In: Math
Consider four nonstandard dice, whose sides are labeled as follows (the 6 sides on each die are equally likely).
A: 4, 4, 4, 4, 0, 0
B: 3, 3, 3, 3, 3, 3
C: 6, 6, 2, 2, 2, 2
D: 5, 5, 5, 1, 1, 1
These four dice are each rolled once. Let A be the result for die A, B be the result for die B, etc.
(a) Find P(A > B), P(B > C), P(C >D), and P(D > A).
(b) Is the event A > B independent of the event B > C? Is the event B > C independent of the event C >D? Explain.
In: Math
discuss the interface of mathematics/statistics, computer science and other disciplines focusing on people, events and ideas
In: Math
To investigate an alleged unfair trade practice, the Federal Trade Commission (FTC) takes a random sample of sixteen “5- ounce” candy bars from a large shipment. The mean of the sample weights is 4.85 ounces and the sample standard deviation is 0.1 ounce. It is reasonable to assume the population of candy bar weights is approximately Normally distributed. Based on this sample, does the FTC have grounds to proceed against the manufacturer for the unfair practice of short-weight selling, on average? Answer this question by completing the following steps of a hypothesis test at the 5% significance level.
d. Do you reject or fail to reject the null hypothesis? Why?
e. Does the FTC have grounds to proceed against the manufacturer for the unfair practice of short-weight selling, on average? Explain your answer.
In: Math
Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us.
(a)
(For each answer, enter a number. Use 2 decimal places.)
n·p =
n·q =
Can we approximate p̂ by a normal distribution? Why? (Fill
in the blank. There are four answer blanks. A blank is represented
by _____.)
_____, p̂ _____ be approximated by a normal random
variable because _____ _____.
first blank
YesNo
second blank
cancannot
third blank
both n·p and n·q exceedn·p and n·q do not exceed n·q exceedsn·q does not exceedn·p exceedsn·p does not exceed
fourth blank (Enter an exact number.)
What are the values of μp̂ and
σp̂? (For each answer, enter a number.
Use 3 decimal places.)
μp̂ = mu sub p hat =
σp̂ = sigma sub p hat =
(b)
Suppose
Can we safely approximate p̂ by a normal distribution?
Why or why not? (Fill in the blank. There are four answer blanks. A
blank is represented by _____.)
_____, p̂ _____ be approximated by a normal random
variable because _____ _____.
first blank
YesNo
second blank
cancannot
third blank
both n·p and n·q exceedn·p and n·q do not exceed n·q exceedsn·q does not exceedn·p exceedsn·p does not exceed
fourth blank (Enter an exact number.)
(c)
Suppose
(For each answer, enter a number. Use 2 decimal places.)
n·p =
n·q =
Can we approximate p̂ by a normal distribution?
Why? (Fill in the blank. There are four answer blanks. A blank is
represented by _____.)
_____, p̂ _____ be approximated by a normal random
variable because _____ _____.
first blank
YesNo
second blank
cancannot
third blank
both n·p and n·q exceedn·p and n·q do not exceed n·q exceedsn·q does not exceedn·p exceedsn·p does not exceed
fourth blank (Enter an exact number.)
What are the values of μp̂ and
σp̂? (For each answer, enter a number.
Use 3 decimal places.)
μp̂ = mu sub p hat =
σp̂ = sigma sub p hat =
In: Math
All work must be done in R programing. Consider this dataset provided to you as prob10.txt c1 t1 c2 t2 c3 t3 c4 t4 2650 3115 2619 2933 2331 2799 2750 3200 1200 1101 1200 1309 1888 1901 1315 980 1541 1358 1401 1499 1256 1238 1625 1421 1545 1910 1652 2028 1449 1901 1399 2002 1956 2999 2066 2880 1777 2898 1999 2798 1599 2710 1754 2765 1434 2689 1702 2402 2430 2589 2789 2899 2332 2300 2250 2741 1902 1910 2028 2100 1888 1901 2000 1899 1530 2329 1660 2332 1501 2298 1478 2287 2008 2485 2104 2871 1987 2650 2100 2520 (2) Read it in and set the row names to “Gene 1” through “Gene 10” It should look like this in R > prob10 c1 t1 c2 t2 c3 t3 c4 t4 Gene 1 2650 3115 2619 2933 2331 2799 2750 3200 Gene 2 1200 1101 1200 1309 1888 1901 1315 980 Gene 3 1541 1358 1401 1499 1256 1238 1625 1421 Gene 4 1545 1910 1652 2028 1449 1901 1399 2002 Gene 5 1956 2999 2066 2880 1777 2898 1999 2798 Gene 6 1599 2710 1754 2765 1434 2689 1702 2402 Gene 7 2430 2589 2789 2899 2332 2300 2250 2741 Gene 8 1902 1910 2028 2100 1888 1901 2000 1899 Gene 9 1530 2329 1660 2332 1501 2298 1478 2287 Gene 10 2008 2485 2104 2871 1987 2650 2100 2520 (3 )Perform a one-sample t-test to compare the hypothesis that the mean of the control expression values is 2000.
In: Math
Determine the margin of error for a confidence interval to estimate the population mean with n=18 and s=12.1 for the confidence levels below.
A) The margin of error for an 80% confidence interval is:
B) The margin of error for an 90% confidence interval is:
C) The margin of error for an 99% confidence interval is:
In: Math