The board of directors for a particular company consists of 10 members, 6 of whom are loyal to the current company president and 4 of whom want to fire the president. Suppose the chair of the board (who is a loyal supporter of the current president) suggests to randomly select 4 other board members to serve on a committee to decide the president’s fate. Find the probability for the first 3 questions and explain your answer for the fourth question. (75–150 words, or 1–2 paragraphs)
-What is the probability that all 5 committee members
will vote to keep the president in place, if no one changes their
minds?
-What is the probability that a majority of the
committee will vote to keep the president in place, if no one
changes their minds?
-What is the probability that the vote is 4 to 1 to
replace the president, if no one changes their minds?
-Imagine that you were the president of the company
and you hoped to keep your position. Considering the various
probabilities, would you consider the chair of the board’s
suggestion to be in your favor or not? If the choice was yours,
would you allow the suggestion to proceed?
In: Math
Summarize the different approach in school safety such as metal detectors arm guard and 0 tolerance Policies
In: Math
Richard has just been given a 4-question multiple-choice quiz in his history class. Each question has five answers, of which only one is correct. Since Richard has not attended class recently, he doesn't know any of the answers. Assuming that Richard guesses on all four questions, find the indicated probabilities. (Round your answers to three decimal places.)
(a) What is the probability that he will answer all questions
correctly?
(b) What is the probability that he will answer all questions
incorrectly?
(c) What is the probability that he will answer at least one of the
questions correctly? Compute this probability two ways. First, use
the rule for mutually exclusive events and the probabilities shown
in the binomial probability distribution table.
Then use the fact that P(r ≥ 1) = 1 −
P(r = 0).
Compare the two results. Should they be equal? Are they equal? If
not, how do you account for the difference?
(d) What is the probability that Richard will answer at least half
the questions correctly?
In: Math
What is the age distribution of patients who make office visits to a doctor or nurse? The following table is based on information taken from a medical journal.
| Age group, years | Under 15 | 15-24 | 25-44 | 45-64 | 65 and older |
| Percent of office visitors | 10% | 5% | 15% | 10% | 60% |
Suppose you are a district manager of a health management organization (HMO) that is monitoring the office of a local doctor or nurse in general family practice. This morning the office you are monitoring has eight office visits on the schedule. What is the probability of the following?
(a) At least half the patients are under 15 years old. (Round
your answer to three decimal places.)
Explain how this can be modeled as a binomial distribution with 8
trials, where success is visitor age is under 15 years old and the
probability of success is 10%?
Let n = 15, p = 0.10 and compute the probabilities using the binomial distribution.Let n = 8, p = 0.10 and compute the probabilities using the binomial distribution. Let n = 8, p = 0.90 and compute the probabilities using the binomial distribution.Let n = 8, p = 0.15 and compute the probabilities using the binomial distribution.
(b) From 2 to 5 patients are 65 years old or older (include 2 and
5). (Round your answer to three decimal places.)
(c) From 2 to 5 patients are 45 years old or older (include 2 and
5). (Hint: Success if 45 or older. Use the table to
compute the probability of success on a single trial. Round your
answer to three decimal places.)
(d) All the patients are under 25 years of age. (Round your answer
to three decimal places.)
(e) All the patients are 15 years old or older. (Round your answer
to three decimal places.)
In: Math
Generate 1000 random numbers from ??3? starting with standard normal random numbers in R.
In: Math
Generate 1000 random numbers from ??2, 5? starting with standard normal random numbers in R.
In: Math
In an article in the Journal of Marketing, Bayus
studied the differences between "early replacement buyers” and
"late replacement buyers” in making consumer durable good
replacement purchases. Early replacement buyers are consumers who
replace a product during the early part of its lifetime, while late
replacement buyers make replacement purchases late in the product’s
lifetime. In particular, Bayus studied automobile replacement
purchases. Consumers who traded in cars with ages of zero to three
years and mileages of no more than 35,000 miles were classified as
early replacement buyers. Consumers who traded in cars with ages of
seven or more years and mileages of more than 73,000 miles were
classified as late replacement buyers. Bayus compared the two
groups of buyers with respect to demographic variables such as
income, education, age, and so forth. He also compared the two
groups with respect to the amount of search activity in the
replacement purchase process. Variables compared included the
number of dealers visited, the time spent gathering information,
and the time spent visiting dealers.
(a) Suppose that a random sample of 796 early replacement buyers yields a mean number of dealers visited of x¯x¯ = 3.1, and assume that σ equals .77. Calculate a 99 percent confidence interval for the population mean number of dealers visited by early replacement buyers. (Round your answers to 3 decimal places.)
The 99 percent confidence interval is
[,
].
(b) Suppose that a random sample of 496 late
replacement buyers yields a mean number of dealers visited of x¯x¯
= 4.8, and assume that σ equals .64. Calculate a 99
percent confidence interval for the population mean number of
dealers visited by late replacement buyers. (Round your
answers to 3 decimal places.)
The 99 percent confidence interval is
[,
].
(c) Use the confidence intervals you computed
in parts a and b to compare the mean number of
dealers visited by early replacement buyers with the mean number of
dealers visited by late replacement buyers. How do the means
compare?
In: Math
Generate 1000 random numbers from a normal distribution with mean 1 and variance 2 using Box‐Muller transformation in R.
In: Math
Trevor is interested in purchasing the local hardware/sporting goods store in the small town of Dove Creek, Montana. After examining accounting records for the past several years, he found that the store has been grossing over $850 per day about 70% of the business days it is open. Estimate the probability that the store will gross over $850 for the following. (Round your answers to three decimal places.)
(a) at least 3 out of 5 business days
(b) at least 6 out of 10 business days
(c) fewer than 5 out of 10 business days
(d) fewer than 6 out of the next 20 business days
(e) more than 17 out of the next 20 business days
In: Math
In: Math
What is the relationship between transportation models and more general logistics models? Explain how these two types of linear optimization models are similar and how they are different.
In: Math
Presidential stature
In a race for U.S. president, is the taller candidate more likely
to win?
1.4.28 In the first election of the 20th century, Theodore
Roosevelt (178 cm) defeated Alton B. Parker (175 cm). There have
been 27 additional elections since then, for a total of 28. Of
these, 25 elections had only two major party candidates with one
taller than the other. In 19 of the 25 elections, the taller
candidate won.
a. Let π = P(taller wins). State the research hypothesis in words
and in symbols.
b. State the null and alternative hypotheses in words and
symbols.
c. Compute the appropriate p-value using an applet.
d. If you take the p-value at face value, what do you
conclude?
e. Are there reasons not to take the p-value at face value? Is yes,
list them
In: Math
Suppose you are dealt 5 random cards from a standard deck of 52 cards, where all cards are equally likely to appear.
(a) What is your outcome space?
(b) What is the probability that you receive the ace of hearts?
(c) Let AH be the event that you receive the ace of hearts, AC the event that you receive the ace of clubs, AD the event that you receive the ace of diamonds, and AS the event that you receive the ace of spades. If A is the event that you receive at least one ace, write A in terms of AH, AC, AD, and AS.
(d) Use the union bound to give an upper bound on the probability of A.
In: Math
Match the following statistical tests with the level of measurement or other requirement required for each analysis.
Pearson r
[ Choose ] Ordinal, very small group size Interval or ratio data Ordinal data Nominal data
Spearman 's Rank Order (rho)
[ Choose ] Ordinal, very small group size Interval or ratio data Ordinal data Nominal data
Kendall's Tau
[ Choose ] Ordinal, very small group size Interval or ratio data Ordinal data Nominal data
Chi Square
[ Choose ] Ordinal, very small group size Interval or ratio data Ordinal data Nominal data
In: Math
The following table shows the annual returns (in percent) and summary measures for a sample of returns from the Vanguard Energy Fund and the Vanguard Health Care Fund from 2012 through 2016.
| Year | Energy (%) | Health Care (%) |
| 2012 | 44.6 | 15.41 |
| 2013 | 19.68 | 10.87 |
| 2014 | 37 | 10.43 |
| 2015 | -42.87 | -18.45 |
| 2016 | 28.36 | 20.96 |
If the risk-free rate is 3%, using mean-variance analysis, which fund performed better, and why?
| a. |
The Energy Fund performed better, because its Sharpe Ratio was higher. |
|
| b. |
The Health Care Fund performed better, because its Sharpe Ratio was lower. |
|
| c. |
The Energy Fund performed better, because its Sharpe Ratio was lower. |
|
| d. |
The Health Care Fund performed better, because its Sharpe Ratio was higher. |
In: Math