Lazer Technologies Inc. (LTI) has produced a total of 20 high-power laser systems that could be used to destroy any approaching enemy missiles or aircraft. The 20 units have been produced, funded in part as private research within the research and development arm of LTI, but the bulk of the funding came from a contract with the U.S. Department of Defense (DoD).
Testing of the laser units has shown that they are effective defense weapons, and through redesign to add portability and easier field maintenance, the units could be truck-mounted.
DoD has asked LTI to submit a bid for 100 units.
The 20 units that LTI has built so far cost the following
amounts and are listed in the order in which they were produced:
Use Exhibit 6.4 and Exhibit 6.5
UNIT NUMBER |
COST ($ MILLIONS) |
UNIT NUMBER |
COST ($ MILLIONS) |
|||||
1 | $ | 13.0 | 11 | $ | 3.7 | |||
2 | 8.8 | 12 | 3.6 | |||||
3 | 7.4 | 13 | 3.4 | |||||
4 | 6.2 | 14 | 3.4 | |||||
5 | 5.7 | 15 | 3.2 | |||||
6 | 5.2 | 16 | 3.2 | |||||
7 | 4.8 | 17 | 3.0 | |||||
8 | 4.5 | 18 | 2.9 | |||||
9 | 4.2 | 19 | 2.8 | |||||
10 | 4.0 | 20 | 2.8 | |||||
a. Based on past experience, what is the learning rate? (Do not round intermediate calculations. Round your answer to the nearest whole percent.)
b. What bid should LTI submit for the total order of 100 units, assuming that learning continues?
c. What is the cost expected to be for the last unit under the learning rate you estimated?
In: Math
|
In: Math
A psychologist would like to examine the effects of different teaching strategies on the final performance of 6th grade students. One group is taught using material presented in class along with outdoor discovery, one group is taught using material taught in class alone, and the third group is taught using only the outdoor discovery method. At the end of the year, the psychologist interviews each student to get a measure of the student’s overall knowledge of the material.
Use an analysis of variance with α = .05 to determine whether these data indicate any significant mean differences among the treatments (teaching strategies). Remember to 1) State the null hypothesis, 2) Show all of your calculations, 3) Make a decision about your null hypothesis, 4) Make a conclusion including an APA format summary of your findings (include a measure of effect size if necessary), and 5) Indicate what you would do next given your findings.
In Class & Outdoor |
In Class Only |
Outdoor Only |
|
4 |
1 |
0 |
|
6 |
4 |
2 |
G = 43 |
3 |
5 |
0 |
ƩX2 = 193 |
7 |
2 |
2 |
|
5 | 2 | 0 | |
T = 25 |
T = 14 |
T = 4 |
|
SS = 10 |
SS = 10.8 |
SS = 4.8 |
In: Math
The table below gives the age and bone density for five randomly selected women. Using this data, consider the equation of the regression line, yˆ=b0+b1x, for predicting a woman's bone density based on her age. Keep in mind, the correlation coefficient may or may not be statistically significant for the data given. Remember, in practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant.
Age | 47 | 49 | 51 | 58 | 63 |
---|---|---|---|---|---|
Bone Density | 360 | 353 | 336 | 333 | 332 |
Step 2 of 6 :
Find the estimated y-intercept. Round your answer to three decimal places.
Summation Table
x | y | xyxy | x2x2 | y2y2 | |
---|---|---|---|---|---|
Sum | 268 | 1714 | 91583 | 1454 | 588218 |
Woman 1 | 47 | 360 | 16920 | 2209 | 129600 |
Woman 2 | 49 | 353 | 17297 | 2401 | 124609 |
Woman 3 | 51 | 336 | 17136 | 2601 | 112896 |
Woman 4 | 58 | 333 | 19314 | 3364 | 110889 |
Woman 5 | 63 | 332 | 20916 | 3969 | 110224 |
I am able to understand how this problem is solve. Can you break it down for me?
In: Math
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and the United Kingdom. They found that a substantially greater percentage of U.K. ads use humor. (a) Suppose that a random sample of 366 television ads in the United Kingdom reveals that 141 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.K. television ads that use humor. (Round your answers to 3 decimal places.) pˆ = The 95 percent confidence interval is [ , ]. (b) Suppose a random sample of 455 television ads in the United States reveals that 122 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.S. television ads that use humor. (Round your answers to 3 decimal places.) pˆ = The 95 percent confidence interval is [ , ]. (c) Do the confidence intervals you computed in parts a and b suggest that a greater percentage of U.K. ads use humor? , the U.K. 95 percent confidence interval is the maximum value in the confidence interval for the U.S.
In: Math
In each of the following cases, compute 95 percent, 98 percent, and 99 percent confidence intervals for the population proportion p. (a) pˆ = .8 and n = 97 (Round your answers to 3 decimal places.) 95 percent confidence intervals is [ , ] 98 percent confidence intervals is [ , ] 99 percent confidence intervals is [ , ] (b) pˆ = .5 and n = 312. (Round your answers to 3 decimal places.) 95 percent confidence intervals is [ , ] 98 percent confidence intervals is [ , ] 99 percent confidence intervals is [ , ] (c) pˆ = .7 and n = 118. (Round your answers to 3 decimal places.) 95 percent confidence intervals is [ , ] 98 percent confidence intervals is [ , ] 99 percent confidence intervals is [ , ] (d) pˆ = .1 and n = 51. (Round your answers to 3 decimal places.) 95 percent confidence intervals is [ , ] 98 percent confidence intervals is [ , ] 99 percent confidence intervals is [ , ]
In: Math
Recall that "very satisfied" customers give the XYZ-Box video game system a rating that is at least 42. Suppose that the manufacturer of the XYZ-Box wishes to use the random sample of 68 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42. (a) Letting µ represent the mean composite satisfaction rating for the XYZ-Box, set up the null hypothesis H0 and the alternative hypothesis Ha needed if we wish to attempt to provide evidence supporting the claim that µ exceeds 42. H0: µ 42 versus Ha: µ 42. (b) The random sample of 68 satisfaction ratings yields a sample mean of x⎯⎯=42.810. Assuming that σ equals 2.70, use critical values to test H0 versus Ha at each of α = .10, .05, .01, and .001. (Round your answer z.05 to 3 decimal places and other z-scores to 2 decimal places.) z = Rejection points z.10 z.05 z.01 z.001 Reject H0 with α = , but not with α = (c) Using the information in part (b), calculate the p-value and use it to test H0 versus Ha at each of α = .10, .05, .01, and .001. (Round your answers to 4 decimal places.) p-value = Since p-value = is less than ; reject H0 at those levels of α but not with α = . (d) How much evidence is there that the mean composite satisfaction rating exceeds 42? There is evidence.
In: Math
EuroWatch Company assembles expensive wristwatches and then sells them to retailers throughout Europe. The watches are assembled at a plant with two assembly lines. These lines are intended to be identical, but line 1 uses somewhat older equipment than line 2 and is typically less reliable. Historical data have shown that each watch coming off line 1, independently of the others, is free of defects with probability 0.98. The similar probability for line 2 is 0.99. Each line produces 500 watches per hour. The production manager has asked you to answer the following questions.
Finally, EuroWatch has a third order for 100 watches. The customer has agreed to pay $50,000 for the order—that is, $500 per watch. If EuroWatch sends more than 100 watches to the customer, its revenue doesn’t increase; it can never exceed $50,000. Its unit cost of producing a watch is $450, regardless of which line it is assembled on. The order will be filled entirely from a single line, and EuroWatch plans to send slightly more than 100 watches to the customer.
If the customer opens the shipment and finds that there are fewer than 100 defect-free watches (which we assume the customer has the ability to do), then he will pay only for the defect-free watches—EuroWatch’s revenue will decrease by $500 per watch short of the 100 required—and on top of this, EuroWatch will be required to make up the difference at an expedited cost of $1000 per watch. The customer won’t pay a dime for these expedited watches. (If expediting is required, EuroWatch will make sure that the expedited watches are defect-free. It doesn’t want to lose this customer entirely.)
You have been asked to develop a spreadsheet model to find EuroWatch’s expected profit for any number of watches it sends to the customer. You should develop it so that it responds correctly, regardless of which assembly line is used to fill the order and what the shipment quantity is. (Hints: Use the BINOM.DIST function, with last argument 0, to fill up a column of probabilities for each possible number of defective watches. Next to each of these, calculate EuroWatch’s profit. Then use a sUMPRODUCT to obtain the expected profit. Finally, you can assume that EuroWatch will never send more than 110 watches. It turns out that this large a shipment is not even close to optimal.)
In: Math
Does anyone know to create a model of a ball and urn model of an American Roulette Wheel? Please provide a detailed model with an explanation of how you came to the conclusion you did. And if possible, provide an example of using the model to solve a problem. Thank you!
In: Math
Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy and storage. Let x be a random variable that represents the number of milligrams of porphyrin per deciliter of blood. In healthy circles, x is approximately normally distributed with mean μ = 45 and standard deviation σ = 14. Find the following probabilities. (Round your answers to four decimal places.)
(a) x is less than 60
(b) x is greater than 16
(c) x is between 16 and 60
(d) x is more than 60 (This may indicate an infection,
anemia, or another type of illness.)
In: Math
Show that the skewness of X~Poisson(λ) is λ^-(1/2)
In: Math
Please give a step by step solution:
The ages of a group of 50 women are approximately normally distributed with a mean of 50 years and a standard deviation of 55 years. One woman is randomly selected from the group, and her age is observed.
a. Find the probability that her age will fall between 56 and 59years.
b. Find the probability that her age will fall between 4747 and 51 years.
c. Find the probability that her age will be less than 35 years.
d. Find the probability that her age will exceed 41 years.
In: Math
Suppose x has a distribution with μ = 65 and σ = 9.
(a) If random samples of size n = 16 are selected, can we say anything about the x distribution of sample means?
No, the sample size is too small.Yes, the x distribution is normal with mean μx = 65 and σx = 9. Yes, the x distribution is normal with mean μx = 65 and σx = 0.6.Yes, the x distribution is normal with mean μx = 65 and σx = 2.25.
(b) If the original x distribution is normal, can we say anything about the x distribution of random samples of size 16?
No, the sample size is too small.Yes, the x distribution is normal with mean μx = 65 and σx = 2.25. Yes, the x distribution is normal with mean μx = 65 and σx = 9.Yes, the x distribution is normal with mean μx = 65 and σx = 0.6.
Find P(61 ≤ x ≤ 66). (Round your answer to four
decimal places.)
In: Math
Let the continuous random variable X have probability density function f(x) and cumulative distribution function F(x). Explain the following issues using diagram (Graphs)
a) Relationship between f(x) and F(x) for a continuous variable,
b) explaining how a uniform random variable can be used to simulate X via the cumulative distribution function of X, or
c) explaining the effect of transformation on a discrete and/or continuous random variable
In: Math
Assume that a driver faces the following loss distribution:
Loss 10,000 0
Probability .04 .96
These two drivers decide to pool their losses with two other drivers with the same loss distribution, and all losses are not correlated, i.e., independent.
6. What is the expected loss for each member of the pool?
7. What is the standard deviation of loss for each member of the
pool?
Now consider another group of four drivers who have formed a separate pool, and who each have this loss distribution( before pooling):
Loss
15,000 10,000 0
Probability
.01 .05 .94
8. What is the expected loss for each member of this new pool of four drivers (after pooling)?
9. What is the standard deviation of loss for each member of this new pool (after pooling)?
10. If all 8 drivers decide to pool their risks, what would the expected loss for each member of this pool of eight drivers be?
In: Math