Show how to answer this in EXCEL ONLY, NO megastat or minitab, etc.. Please highlight what data tools or formulas were used.
A survey investigated the public’s attitude toward the federal deficit. Each sampled citizen was classified as to whether he or she felt the government should reduce the deficit or increase the deficit, or if the individual had no opinion. The sample results of the study by gender are reported to below.
Gender | Reduce the Deficit | Increase the Deficit | No Opinion |
Female | 224 | 194 | 68 |
Male | 305 | 114 | 25 |
At the .05 significance level, is it reasonable to conclude that gender is independent of a person’s position on the deficit?
In: Math
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals.
A random sample of 60 home theater systems has a mean price of $111.00. Assume the population standard deviation is $16.20.
The 90% confidence interval is(--,--)
The 99% confidence interval is(--,--)
Which interval is wider?
In: Math
. You measure 36 textbooks' weights, and find they have a mean
weight of 30 ounces. Assume the population standard deviation is 10
ounces. Based on this, construct a 90% confidence interval for the
true population mean textbook weight.
Give your answers as decimals, to two places
Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval for a sample of size 155 with 138 successes. Enter your answer using decimals (not percents) accurate to three decimal places.
You measure 48 turtles' weights, and find they have a mean
weight of 57 ounces. Assume the population standard deviation is
13.8 ounces. Based on this, determine the point estimate and margin
of error for a 95% confidence interval for the true population mean
turtle weight.
Give your answers as decimals, to two places
In: Math
Ask Your Teacher Recent studies have shown that about 20% of American adults fit the medical definition of being obese. A large medical clinic would like to estimate what percentage of their patients are obese, so they take a random sample of 100 patients and find that 16 are obese. Suppose that in truth, the same percentage holds for the patients of the medical clinic as for the general population, 20%. If the clinic took repeated random samples of 100 observations and found the sample proportion who were obese, into what interval should those sample proportions fall about 95% of the time? (Round your answers to two decimal places. Between _____ and _____
In: Math
You wish to test the following claim at a significance level of
α=0.02
H0:μ=62.5
H1:μ>62.5
You believe the population is normally distributed, but you do not
know the standard deviation. You obtain a sample of size 64 with
mean 66.5 and a standard deviation of 12.7.
What is the test statistic for this sample? (Report answer accurate
to 3 decimal places.)
test statistic =
What is the p-value for this sample? (Report answer accurate to
4 decimal places.)
p-value =
In: Math
The number of men and women among professors in Math, Physics, Chemistry, Linguistics, and English departments from a SRS of small colleges were counted, and the results are shown in the table below.
Dept. Math Physics Chemistry Linguistics English
Men 16 . 36 12 10 14
Women 2 . 5 . 4 . 2 . 8
Test the claim that the gender of a professor is independent of the department. Use the significance level α=0.025
(a) The test statistic is χ2=
(b) The critical value is χ2=
(c) Is there sufficient evidence to warrant the rejection of the claim that the gender of a professor is independent of the department? A. No B. Yes
In: Math
In a sample of 169 trees, we found that a pear tree grow to average height of 32 feet and a sample standard deviation of 5 feet. The distribution is approximately normal. Find the 95% confidence interval for the mean population.
In: Math
For a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears. Minitab was used to find that the value of the linear correlation coefficient is r=0.931 Using alphaα=0.05, determine if there is a linear correlation between chest size and weight. What proportion of the variation in weight can be explained by the linear relationship between weight and chest size?
a. Is there a linear correlation between chest size and weight?
A.Yes, because the absolute value of r exceeds the critical value of 0.707
B.No, because the absolute value of r exceeds the critical value of 0.707.
C.Yes, because r falls between the critical values of −0.707 and 0.707.
D. The answer cannot be determined from the given information.
b. What proportion of the variation in weight can be explained by the linear relationship between weight and chest size?
In: Math
A company wants to build a plant but is considering the size. The table below shows their payoffs under different states of demand.
Demand | ||
Low (p=0.45) | High (p=0.55) | |
Small Plant | 500000 | 500000 |
Medium Plant | 200000 | 800000 |
Large Plant | -200000 | 1000000 |
They can hire a consultant who can conduct a survey to evaluate demand. The consultant will report to the company whether demand is strong or weak. The probabilities are 0.60 and 0.40 for strong and weak survey results respectively. The conditional probabilities for demand given survey results are as follow:
P(Low/Strong) = 0.35; P(High/Strong) = 0.65;
P(Low/Weak) = 0.70; P(High/Weak) = 0.30;
a) Draw the decision tree for this problem including with and without a survey.
b) What is the best decision without a survey?
c) What is the decision strategy when survey is conducted?
d) What is the EVPI?
e) What is the EVII
In: Math
A random variable X has density function f(x) = 4x ( 1 + x2)-3 for x > 0.
Determine the mode of X.
In: Math
A survey of 1060people who took trips revealed that 94 of them included a visit to a theme park. Based on those survey results, a management consultant claims that less than 11 % of trips include a theme park visit. Test this claim using the ?=0.01significance level.
(a) The test statistic is ___
(b) The P-value is ___
(c) The conclusion is
A. There is sufficient evidence to support the
claim that less than 11 % of trips include a theme park
visit.
B. There is not sufficient evidence to support the
claim that less than 11 % of trips include a theme park visit.
Independent random samples, each containing 90 observations,
were selected from two populations. The samples from populations 1
and 2 produced 36 and 26 successes, respectively.
Test ?0:(?1−?2)=0against ??:(?1−?2)>0 Use ?=0.1
(a) The test statistic is ___
(b) The P-value is ___
(c) The final conclusion is
A. There is not sufficient evidence to reject the
null hypothesis that (?1−?2)=0
B. We can reject the null hypothesis that
(?1−?2)=0 and conclude that (?1−?2)>0
In: Math
A random sample of 1500 residential telephones in Phoenix found
that 385 of the numbers were unlisted. A random sample in the same
year of 1200 telephones in Scottsdale found that 311 were
unlisted.
Round your answers to four decimal places (e.g. 98.7654).
(a) Calculate a 95% two-sided confidence interval on the difference
in the proportions of unlisted numbers between the two
cities.
Enter your answer; 95% confidence interval, lower bound ≤p1-p2≤
Enter your answer; 95% confidence interval, upper bound
(b) Is there a significant difference between the two proportions
at α = 0.05? Choose your answer in accordance to the item
b) of the question statement
No.Yes.
(c) Calculate a 90% two-sided confidence interval on the difference
in the proportions of unlisted numbers between the two
cities.
Enter your answer; 90% confidence interval, lower bound ≤p1-p2≤
Enter your answer; 90% confidence interval, upper bound
In: Math
A local bank needs information concerning the account balance of its customers. A random sample of 15 accounts was checked. The mean balance was $686.75 with a standard deviation of $256.20.
A. Construct a 98% confidence interval for the population mean, assuming account balances are normally distributed.
B. Based on your previous answer, would a population mean of $500 be unusual? What about a mean of $800?
In: Math
The personnel office at a large electronics firm regularly schedules job interviews and maintains records of the interviews. From the past records, they have found that the length of a first interview is normally distributed, with mean μ = 37 minutes and standard deviation σ = 6 minutes. (Round your answers to four decimal places.)
(a) What is the probability that a first interview will last 40
minutes or longer?
(b) Two first interviews are usually scheduled per day. What is the
probability that the average length of time for the two interviews
will be 40 minutes or longer?
In: Math
Access the hourly wage data on the below Excel Data File (Hourly Wage). An economist wants to test if the average hourly wage is less than $28. Assume that the population standard deviation is $8.
b-1. Find the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.)
Hourly Wage | Education | Experience | Age | Gender |
---|---|---|---|---|
39.00 | 11 | 2 | 40 | 1 |
21.02 | 4 | 1 | 39 | 0 |
42.36 | 4 | 2 | 38 | 0 |
20.17 | 5 | 9 | 53 | 1 |
22.57 | 6 | 15 | 59 | 1 |
43.43 | 6 | 12 | 36 | 1 |
17.87 | 9 | 5 | 45 | 0 |
24.62 | 4 | 12 | 37 | 0 |
28.36 | 5 | 14 | 37 | 1 |
10.25 | 11 | 3 | 43 | 1 |
27.14 | 8 | 5 | 32 | 0 |
10.35 | 9 | 18 | 40 | 1 |
27.09 | 7 | 1 | 49 | 1 |
21.34 | 4 | 10 | 43 | 0 |
19.71 | 1 | 9 | 31 | 0 |
32.41 | 9 | 22 | 45 | 0 |
22.80 | 11 | 3 | 31 | 1 |
26.07 | 4 | 14 | 55 | 0 |
42.14 | 6 | 5 | 30 | 1 |
21.42 | 9 | 3 | 28 | 0 |
21.52 | 6 | 15 | 60 | 1 |
34.00 | 4 | 13 | 32 | 0 |
38.85 | 4 | 9 | 58 | 1 |
29.06 | 5 | 4 | 28 | 0 |
12.60 | 6 | 5 | 40 | 1 |
27.64 | 6 | 2 | 37 | 0 |
32.28 | 4 | 18 | 52 | 1 |
33.46 | 6 | 4 | 44 | 0 |
18.05 | 6 | 4 | 57 | 0 |
28.56 | 9 | 3 | 30 | 1 |
13.41 | 5 | 8 | 43 | 0 |
43.54 | 7 | 6 | 31 | 1 |
33.23 | 4 | 3 | 33 | 0 |
27.34 | 6 | 23 | 51 | 1 |
18.41 | 4 | 15 | 37 | 0 |
31.82 | 4 | 9 | 45 | 0 |
31.30 | 6 | 3 | 55 | 0 |
In: Math