Question

Select the product of the following nuclear reaction: 5024Cr+12 6C→2 10n + ? Express your answer as an element symbol including subscripts and superscripts.

f you had a high-energy xenon particle beam and wanted to make gold, what element would you bombard?

? +143 54Xe→197 79Au+10n

Express your answer as an element symbol including subscripts and superscripts.

Answer 1

Given reaction is, \({ }_{24}^{00} \mathrm{Cr}+{ }_{6}^{12} \mathrm{C} \longrightarrow 2{ }_{0}^{1} n+?\)

Assume that the missing particle \({ }_{z}^{A} X\). In a nuclear reaction, the sum of atomic numbers and mass numbers of

on both sides must be equal.

Thus,

\(24+6=0+z\)

\(Z=30\)

Element with atomic number 30 is \(\mathrm{Zn}\). \(50+12=2 \times 1+A\)

\(A=60\)

Therefore, the missing product is \({ }_{30}^{60} \mathrm{Zn}\)

Given reaction is, \(?+{ }_{54}^{143} \mathrm{Xe} \longrightarrow{ }_{79}^{197} \mathrm{Au}+{ }_{0}^{1} n\)

Assume that the missing reactant is \({ }_{Z}^{A} X\) In a nuclear reaction, the sum of atomic numbers and mass numbers of on both sides must be equal.

Thus,

\(Z+54=79+0\)

\(Z=25\)

The element with atomic number 25 is \(\mathrm{Mn}\).

\(A+143=197+1\)

\(A=55\)

Therefore, the missing reactant is \({ }_{25}^{55} \mathrm{Mn}\)