In: Statistics and Probability
Question 2: Related-Samples t-Test
Paired Samples Statistics |
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Mean |
N |
Std. Deviation |
Std. Error Mean |
||
Pair 1 |
freshman yr science score |
51.8500 |
200 |
9.90089 |
.70010 |
senior yr science score |
53.0450 |
200 |
12.10145 |
.85570 |
Paired Samples Correlations |
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N |
Correlation |
Sig. |
||
Pair 1 |
freshman yr science score & senior yr science score |
200 |
.878 |
.000 |
Paired Samples Test |
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Paired Differences |
t |
df |
Sig. (2-tailed) |
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Mean |
Std. Deviation |
Std. Error Mean |
95% Confidence Interval of the Difference |
||||||
Lower |
Upper |
||||||||
Pair 1 |
freshman yr science score - senior yr science score |
-1.19500 |
5.83241 |
.41241 |
-2.00826 |
-.38174 |
-2.898 |
199 |
.004 |
Solution :-
(a):-
From given analysis, Science score is the Dependent variable.
(b):-
During their freshman and senior years in the school, They test the students on the dependent variable (i.e, science score).
(c):-
The example included N = 200 students that were tested in science in their Freshman recruit and senior years in school.
Freshman science score:
Mean,M = 51.8500.
Standard deviation,SD = 9.90089
Standard error of the mean = 0.70010
Senior year science score:
Mean,M = 53.0450.
Standard deviation, SD = 12.10145
Standard error of the mean = 0.85570.
(d):-
The null hypothesis for this examination was that there will be no significant contrast in 200 students science scores between their Freshman and senior years in school.
The alternative hypothesis for this examination was that there will be a significant contrast in 200 students science scores between their Freshman and senior years in school.
(a):- Write out the t-test formula using the numbers given in the output?
Here we know the formula, i.e,
From given data,
i.e,
(b):- Complete Hypothesis Test Step 4 by completing the following items:
(i):- Decision about null hypothesis?
Since the estimation of ±1.980 does not exceed the estimation of - 2.898, Hence we can reject the null hypothesis.
Additionally, since the significance value (2 - tailed) of 0.004 is less than the alpha of 0.05, Hence, the null hypothesis is rejected.
(ii):- Is it significant?
Yes, this is significant that there is a sufficient evidence for science scores between 200 participants and the population
(ii):- Sentence in APA style.
This results indicate that there is a significant difference in science scores between 200 participants and the population.