In: Civil Engineering
Design a staircase for a two story building with the given loads: DL = 72 psf LL = 60 psf The building floor height = 8ft for a total height of 16 ft. The staircase design must comply with the A.D.A. requirement for a hospital building. Design calculations must be in english units (ft, inches, pnds etc).
1.DATA: | ||||||
number of steps in the flight= | 8 | |||||
tread T = | 270 | mm | ||||
Rise R= | 130 | mm | ||||
Width of landing beams= | 300 | mm | ||||
fck= | 20 | N/mm2 | ||||
fy= | 415 | N/mm2 | ||||
width of stair case b= | 1000 | mm | ||||
2.EFFECTIVE SPAN: | ||||||
Effective span =(no of steps *thread )+width of landing beam | ||||||
Effective span = | 2460 | mm= | 2.46 | m | ||
thickness of waist slab =span /20= | 123 | mm | ||||
adopt overall depth = D= | 123 | mm | ||||
effective depth=d= | 98 | mm= |
total dead load = | 3.447379 | KN/m | ||||||||||||
service live load= | 2.872816 | KN/m | ||||||||||||
total load= | 6.320194 | KN/m | ||||||||||||
factored load = wu= 1.5*t.l = | 9.48029126 | KN/m | ||||||||||||
4.BENDING MOMENTS: | ||||||||||||||
maximum bending moment at centre of span is | ||||||||||||||
Mu = | 0.125 WuL2 | |||||||||||||
Mu = | 47.03409501 | KN.m | ||||||||||||
5.CHECK OF DEPTH OF WAIST SLAB: | ||||||||||||||
Mu=0.138fckbd2 | ||||||||||||||
by solving d = | 130.5425 | mm< | 290 | mm | ||||||||||
hence safe | ||||||||||||||
6.MAIN REINFORCEMENTS: | ||||||||||||||
|
calculations | |||||||||||||
Mu=0.87fy Ast d | 0.1286307 | |||||||||||||
0.8713693 | ||||||||||||||
0.9334716 | ||||||||||||||
by solving Ast = | 464.8969828 | mm2 | 0.0665284 | |||||||||||
464.89698 | ||||||||||||||
dia of bar= | 12 | mm | ||||||||||||
no of bar = | 4.112677 | nos | 113.04 | |||||||||||
so Ast = | 464.897 | mm2 | ||||||||||||
provide 12mm diameter bar at 200mm centres as mainreinforcement | ||||||||||||||
7.DISTRIBUTION REINFORCEMENT: | ||||||||||||||
distribution reinforcement = 0.12 percent of cross section | ||||||||||||||
= | 378 |
m
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