Question

In: Math

Miles Freq 0-4 3 5-9 14 10-14 13 15-19 4 Write two sentences for non-statisticians expressing...

Miles  Freq
 0-4     3
 5-9    14
10-14   13
15-19    4

Write two sentences for non-statisticians expressing Chebyshev’s Theorem. Select the most appropriate sentence corresponding to two standard deviations.



*About 68% of students drive between 5.5212 miles and 13.7730 miles to somewhere
*At least 88.9% of students drive between -2.7306 miles and 22.0248 miles to 
*About 99.7% of students drive between 1.3953 miles and 17.8989 miles to 
*About 68% of students drive less than 22.0248 miles to
*About 95% of students drive between 5.5212 miles and 13.7730 miles to
*About 99.7% of students drive between -2.7306 miles and 22.0248 miles to
*About 68% of students drive between 1.3953 miles and 17.8989 miles to
*About 99.7% of students drive between 5.5212 miles and 13.7730 miles to
*At least 75% of students drive between -2.7306 miles and 22.0248 miles to
*At least 75% of students drive less than 22.0248 miles to
*About 95% of students drive between 1.3953 miles and 17.8989 miles to
*At least 75% of students drive between 1.3953 miles and 17.8989 miles to
*About 95% of students drive less than 22.0248 miles to 
*At least 88.9% of students drive between 1.3953 miles and 17.8989 miles to
*About 99.7% of students drive less than 22.0248 miles to
*About 95% of students drive between -2.7306 miles and 22.0248 miles to
*At least 88.9% of students drive less than 22.0248 miles to
*About 68% of students drive between -2.7306 miles and 22.0248 miles to

Solutions

Expert Solution

First we need to find the mean and SD of data:

Miles X Freq, f xf f(x-mean)^2
0-4 2 3 6 175.4344152
5-9 7 14 98 98.09993774
10-14 12 13 156 71.96979933
15-19 17 4 68 216.2605536
Total 34 328 561.7647059

Sample size:

The mean is:

The standard deviation is:

Interval corresponding to 2 standard deviations of mean is:

According to Chebyshev's theorem at least 75% data values lie within 2 standard deviations of mean. That is according to Chebyshev's theorem at least 75% data values lie within interval (1.3953, 17.7189).

-------------

Interval corresponding to 3 standard deviations of mean is:

According to Chebyshev's theorem at least 88.9% data values lie within 2 standard deviations of mean. That is according to Chebyshev's theorem at least 75% data values lie within interval (-2.7306, 22.0248).

Correct options are:

At least 75% of students drive between 1.3953 miles and 17.8989 miles
At least 88.9% of students drive between -2.7306 miles and 22.0248 miles

Related Solutions

Miles Freq 0-4 3 5-9 14 10-14 13 15-19 4 Select the most appropriate sentence corresponding...
Miles Freq 0-4 3 5-9 14 10-14 13 15-19 4 Select the most appropriate sentence corresponding to two standard deviations. *About 68% of students drive between 5.5212 miles and 13.7730 miles to somewhere *At least 88.9% of students drive between -2.7306 miles and 22.0248 miles to *About 99.7% of students drive between 1.3953 miles and 17.8989 miles to *About 68% of students drive less than 22.0248 miles to *About 95% of students drive between 5.5212 miles and 13.7730 miles to...
Day 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15...
Day 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Number of Aides Absent 5 8 11 15 4 2 7 1 4 6 14 19 3 5 8 In which of the following ranges you can find the Upper Control Limit of the control chart? 0.1427 0.1536 0.1677 Not computable with information available In which of the following ranges you can find the Lower Control Limit of the control chart? Does not exit...
student 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15...
student 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Test score 67 67 87 89 87 77 73 74 68 72 58 98 98 70 77 Above we have the final averages of the last stats and I want to know if the class average falls within the boundaries of all my statistics classes for the past 20 years. Find the sample size, mean, and standard deviation of the data above (Table 1)....
Promotional expenses(x) Sales(y 7 12 10 14 9 13 4 5 11 15 5 7 3...
Promotional expenses(x) Sales(y 7 12 10 14 9 13 4 5 11 15 5 7 3 4 a) draw the scatter plot and draw the line of best fit b) Calculate and interpret the correlation between promotional expenses and sales C) Calculate the regression equation( calculate the slope and intercept of the regression line d)Interpret the slop coefficient of regression equation e)Using the regression equation calculate the sales volume with respect to promotional expense of 4. f) Obtain the coefficient...
Match No. 1 2 3 4 5 6 7 8 9 10 11 12 13 14...
Match No. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Player A 8 42 56 68 91 123 12 46 57 137 5 80 14 10 19 Player B 38 44 46 59 57 61 48 42 51 39 58 41 55 45 68 1. For the given data set representing the runs scored by two players in last 15 matches, conduct the following analysis: i. Which average you will use to summarize...
Company ID 1 2 3 4 5 6 7 8 9 10 11 12 13 14...
Company ID 1 2 3 4 5 6 7 8 9 10 11 12 13 14 1 5330 6352 6340 3399 6566 7376 6882 1842 7362 8205 6222 7695 1681 2283 2 7972 5941 2861 3290 1019 7399 6442 8003 5092 4634 7569 2538 2619 7932 3 8545 6667 2121 2339 4770 7296 3215 7919 2176 9129 1321 695 7945 1673 4 4578 466 4142 8350 7439 6085 8381 5872 2703 6974 702 5846 7176 9179 5 7302 2727 3103...
Post Position 1 2 3 4 5 6 7 8 9 10 Wins 19 14 11...
Post Position 1 2 3 4 5 6 7 8 9 10 Wins 19 14 11 15 15 7 8 12 5 11 The table below lists the frequency of wins for different post positions in the Kentucky Derby horse race. Use a 0.05 significance level to test the claim that the likelihood of winning is the same for the different post positions. What is the critical value (the X2 value)? [Round to the nearest thousandths place]
Periods ​1% ​2% ​3% ​4% ​5% ​6% ​7% ​8% ​9% ​10% ​12% ​14% ​15% ​16% ​18%...
Periods ​1% ​2% ​3% ​4% ​5% ​6% ​7% ​8% ​9% ​10% ​12% ​14% ​15% ​16% ​18% ​20% 1 0.990 0.980 0.971 0.962 0.952 0.943 0.935 0.926 0.917 0.909 0.893 0.877 0.870 0.862 0.847 0.833 2 0.980 0.961 0.943 0.925 0.907 0.890 0.873 0.857 0.842 0.826 0.797 0.769 0.756 0.743 0.718 0.694 3 0.971 0.942 0.915 0.889 0.864 0.840 0.816 0.794 0.772 0.751 0.712 0.675 0.658 0.641 0.609 0.579 4 0.961 0.924 0.888 0.855 0.823 0.792 0.763 0.735 0.708 0.683 0.636...
Analyze the assertions and principles of Scripture found in Ecclesiastes 5:10-11, Luke 3:13-14, Philippians 4:10-13, and...
Analyze the assertions and principles of Scripture found in Ecclesiastes 5:10-11, Luke 3:13-14, Philippians 4:10-13, and 1 Timothy 6:1-16. How do these passages apply to economics? How do they affect and impact a Christian understanding of economics? 250 words or more
Consider the grouped frequency distribution. Class Limits 3-5 6-8 9-11 12-14 15-17 f 4 10 10...
Consider the grouped frequency distribution. Class Limits 3-5 6-8 9-11 12-14 15-17 f 4 10 10 5 10 (a) Find the mean. (Give your answer correct to two decimal places.) (b) Find the variance. (Give your answer correct to two decimal places.) (c) Find the standard deviation. (Give your answer correct to two decimal places.)
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT