In: Statistics and Probability
An experiment on the side effects of pain relievers assigned
arthritis patients to take one of several over-the-counter pain
medications. Of the 430 patients who took one brand of pain
reliever, 24 suffered some "adverse symptom." Does the experiment
provide strong evidence that fewer than 8% of patients who take
this medication have adverse symptoms?
(a) H0: p ---Select--- < >
= and Ha: p ---Select--- > ≥
< ≤ ≠ =
(b) The test statistic is (Use 2 decimal places)
(c) The p-value is (Use 4 decimal places)
(d) Therefore, we can conclude that
The data does provide statistical evidence at the 0.05 significance level that fewer than 8% of arthritis patients taking the pain medication experience adverse symptoms
.The data does provide statistical evidence at the 0.05 significance level that fewer than 8% of these 430 arthritis patients taking the pain medication experience adverse symptoms
.The data does not provide statistical evidence at the 0.05 significance level that fewer than 8% of arthritis patients taking the pain medication experience adverse symptoms.
The data does provide statistical evidence at the 0.05 significance level that 5.58% of arthritis patients taking the pain medication experience adverse symptoms.
Solution :
Given that,
= 8% = 0.08
1 - = 1 - 0.08 = 0.92
n = 430
x = 24
Level of significance = = 0.05
Point estimate = sample proportion = = x / n = 24 / 430 =
This a left (One) tailed test.
a)
Ho: p = 0.08
Ha: p < 0.08
b)
Test statistics
z = ( - ) / *(1-) / n
= ( 0.0558 - 0.08) / (0.08*0.92) / 430 = 0.0558
= -1.85
c)
P-value = P(Z < z)
= P(Z < -1.85)
= 0.0322
The p-value is p = 0.0322, and since p = 0.0322 < 0.05, it is concluded that the null hypothesis is rejected.
Conclusion:
The data does provide statistical evidence at the 0.05 significance level that fewer than 8% of arthritis patients taking the pain medication experience adverse symptoms