Question

In: Statistics and Probability

A random sample of companies in electric utilities (I), financial services (II), and food processing (III)...

A random sample of companies in electric utilities (I), financial services (II), and food processing (III) gave the following information regarding annual profits per employee (units in thousands of dollars).

I II III
49.4 55.4 38.8
43.4 25.2 37.8
32.1 41.9 10.4
27.3 29.9 32.5
38.7 39.6 15.7
36.3 42.3
20.3

Shall we reject or not reject the claim that there is no difference in population mean annual profits per employee in each of the three types of companies? Use a 1% level of significance.

(a). what is the level of significance

(b).  Find SSTOT, SSBET, and SSW and check that SSTOT = SSBET + SSW. (Use 3 decimal places.)

SSTOT =
SSBET =
SSW =


Find d.f.BET, d.f.W, MSBET, and MSW. (Use 3 decimal places for MSBET, and MSW.)

dfBET =
dfW =
MSBET =
MSW =


Find the value of the sample F statistic. (Use 3 decimal places.)

What are the degrees of freedom?
(numerator)
(denominator)

(c). Make a summary table for your ANOVA test.

Source of
Variation
Sum of
Squares
Degrees of
Freedom
MS F
Ratio
P Value Test
Decision
Between groups
Within groups
Total

Solutions

Expert Solution

Consider

y1: Annual profits per employee in electrical utilities

y2: Annual profits per employee in financial services.

y3: Annual profits per employee in food processing company.

We have to test the hypothesis

There is no significant difference in population mean annual profits per employee in each of the three types of company at 1% level of significance.

i.e. Null Hypothesis -

against

Alternative hypothesis - Ha: At least two are different.

a) Alpha = level of significance = 0.01.

b )

Y1 Y2 Y3 (Y1-Y1bar)^2 (Y2-Y2bar)^2 (Y3-Y3bar)^2
49.4 55.4 38.8 197.2030 289 84.9476
43.4 25.2 37.8 64.6882 174.24 67.5142
32.1 41.9 10.4 10.6087 12.25 367.9990
27.3 29.9 32.5 64.9169 72.25 8.5071
38.7 39.6 15.7 11.1750 1.44 192.7460
36.3 42.3 0.8891 161.7145
20.3 226.7163
247.5 192 177.5 576.1971 549.1800 883.4283

n1 = 7 , n2= 5 , n3 = 6

N = 7 + 5+ 6= 18

G = Grand Total = 247.5 + 192 + 177.5 = 617

Ybar = Grand Mean = 617/18 = 34.2778

y1bar = 247.5 / 7 = 35.3571.

y2bar =192 / 5 = 38.40.

y1bar = 177.5 / 6= 29.5833.

Correction factor =C.F= G2 / N = 6172 / 18 = 21149.3889.

Raw Sum of square (RSS) = 49.4 2 + .............. + 42.3 2 = 23383.54

Total Sum of square = SSTOT = RSS - C.F. = 23383.54 - 21149.3889 = 2234.1511.

SSTOT = 2234.151.

Between Sum of square = SSBET

SSBET = n1 * ( y1bar-ybar)2 + n2 *(y2bar-ybar)2 + n3 * ( y3bar-ybar)2.

= 7 * ( 35.3571 - 34.2778)2+ 5 * ( 38.40- 34.2778)2+ 6 * ( 29.5833 - 34.2778)2

SSBET = 225.346.

Within Sum of square = SSW

= Sum ( Y1 - Y1bar)2 + Sum ( Y2-Y2bar)2 + sum(Y3-Y3bar)2

= 576.1971 + 549.1800 + 883.4283

= 2008.805

SSW = 2008.805

SSBET +SSW = 225.346 + 2008.805 = 2234.151 = SSTOT.

Degrees of Freedom

Number of companies = k =3

dfBet = k-1 = 2

Total number of observations =N = 18.

dfW = N-K = 18 -3 = 15

MSBET = SSBET /dfBet = 225.346 / 2 = 112.673.

MSW =SSW/dfW = 2008.805 / 15 = 133.920.

Value of the sample F statistic is

F = MSBet / MSW ~ F k-1, N-k.

F = 112.973 / 133.920 = 0.8413

Degrees of freedom for numerator = 2

Degrees of freedom for denominator = 15.

Since value of F-statistic is 0.8413

p-value is given by

p-value = P ( F2,15 > 0.8413) = 0.4505

Decision : Since p-value > level of significance, we fail to reject Ho .

Conclusion : There is sufficient evidence support to claim that there is no significant difference in population mean annual profits per employee in each of the three types of company.

c) Anova table:

Source of Variation SS df MS F P-value Test
Between Groups 225.3456 2 112.6728 0.841342 0.4505 Accept Ho.
Within Groups 2008.805 15 133.9204
Total 2234.151 17

Alternative Solution by using Excel

Y1 Y2 Y3
49.4 55.4 38.8
43.4 25.2 37.8
32.1 41.9 10.4 Anova: Single Factor
27.3 29.9 32.5
38.7 39.6 15.7 SUMMARY
36.3 42.3 Groups Count Sum Average Variance
20.3 Column 1 7 247.5 35.35714 96.03286
Column 2 5 192 38.4 137.295
Column 3 6 177.5 29.58333 176.6857
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 225.3456 2 112.6728 0.841342 0.450495 3.68232
Within Groups 2008.805 15 133.9204
Total 2234.151 17

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