Use R to solve: Find the approximate solution x' to : 0.89x1 + 0.53x2 = 0.36...

Use R to solve:

Find the approximate solution x' to :

0.89x1 + 0.53x2 = 0.36

0.47x1 + 0.28x2 = 0.19

Find the error x'-x* between the computed solution and the true solution.

Compare the size of this error with the size of the residual r=b-Ax'

Solutions

Expert Solution

The R program to find the approximate solution is as follows:-

INPUT:-

#We crarete a 2*2 matrix A which is the augmented matrix of the system of linear equations and b is the R.H.S of system of #linear equations,We use ginv() function from MASS library to get the generalised inverse of A
A <- matrix(c(0.89,0.47,0.53,0.28),2,2)
b <-c(0.36,0.19)
library(MASS)
ginv(A) %*% b

OUTPUT:-

[,1]
[1,] 1
[2,] -1

Hence our approximate solution is x'=(1, -1)^T so x1=1 and x2= -1

Colby Messinger answered 2 years ago

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