In: Statistics and Probability
Independent random samples of sizes n1 = 307 and n2 = 309 were taken from two populations. In the first sample, 92 of the individuals met a certain criteria whereas in the second sample, 108 of the individuals met the same criteria.
Test the null hypothesis H0:p1=p2versus the alternative hypothesis HA:p1<p2.
a) Calculate the z test statistic, testing the null hypothesis that the population proportions are equal.
Round your response to at least 3 decimal places.
b) What is the approximate value of the p-value?
Round your response to at least 3 decimal places.
c) What is the appropriate conclusion that can be made?
There is sufficient evidence to reject the null hypothesis at the 5% level of significance, but insufficienct evidence to reject the null hypothesis at the 10% level of significance. | ||
There is insufficient evidence to reject the null hypothesis at both the 5% and 10% levels of significance. | ||
There is sufficient evidence to reject the null hypothesis at the 10% level of significance, but insufficient evidence to reject the null hypothesis at the 5% level of significance. | ||
There is sufficient evidence to reject the null hypothesis at both the 10% and 5% levels of significance. |
n1 = 307 , n2 = 309
x1= 92, x2= 108
Ho:p1=p2
Ha:p1<p2
a) Calculate the z test statistic
Z = -1.321
test statistic = -1.321
b) Calculate the p-value
P-Value = P(Z < -1.321)
find P(Z < -1.321) using normal z table we get
P(Z < -1.321) = 0.0933
P-Value = 0.0933
c)
now if = 0.05
(P-Value = 0.0933) > ( = 0.05)
then null hypothesis is not rejected.
now if = 0.10
(P-Value = 0.0933) < ( = 0.10)
then null hypothesis is rejected.
There is sufficient evidence to reject the null hypothesis at the 10% level of significance, but insufficient evidence to reject the null hypothesis at the 5% level of significance.